An AC voltage is applied to a purely capacitive circuit. Just as the applied voltage is crossing the zero axis going negative, w
1 answer:
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Answer:
a)6.7m/S
b)6.8m/s
Explanation:
Hello ! To solve the point b you must follow the steps below
1.Draw the slide taking into account its length and height and find the angle from which the swimmer is launched (see attached image)
2. Find the horizontal velocity (X) and vertical (Y) components (see attached image)
3) for the third step we must remember that as in the slide there is no horizontal acceleration the speed in X will remain constant at the end of the swimmer's path (Vx = 0.59m / s)
4)
the fourth step is to remember that vertically there is constant acceleration called gravity (g = 9.81m / s ^ 2), so to find the speed at the end of the route we use the following equation
where
Vfy= final verticaly speed
Vy=initial verticaly speed=0.59m/S
g=gravity=9.81m/S^2
y=height of slide=2.31m
solving
The last step is to add the velocity components vectorally at the end of the route with the following equation
point A
taking into account the previous steps we can infer that as the swimmer starts from rest, the velocity (Vx=Vy=O) is zero, so we should only use the formula for constant acceleration movement.
vy=0
Vfy==6.7m/s
Answer:
(a) dime
Explanation:
Convert all to metric unit:
0.5 cm = 0.005 m
1.8 cm = 0.018 m
71 cm = 0.71 m
In order to find out we would need to calculate the ratio R between the object diameter d and their distance s to our eyes:
Since the ratio of the dime is larger than the ratio of the moon, and the ratio of the pea is smaller than the ratio of the moon, only the (a) dime can cover your view of the moon.
Answer with explanation:
We are given that
Mass of ball,75 g=
1 kg=1000 g
Height,
Horizontal velocity,
Mass of plate
a.Initial velocity of plate,
Velocity before impact=
Where
Velocity after impact,
According to law of conservation of momentum
Substitute the values
Velocity of plate=1.69 m/s
b.Initial energy=
Final energy=
Final energy=
Energy lost due to compact=Initial energy-final energy=1.326-1.162=0.164 J