Consider the wave function for a particle in a box of size L,

Moment of inertia: A dumbbell-shaped object is composed by two equal masses, m, connected by a rod of negligible mass and length

LekaFEV [45]

Answer:

B.Less than

Explanation:

We are given that

Mass of each object=m

Length of rod=r

$I_1$ =Moment of inertia of the dumbbell shaped object with respect to an axis passing through the center of the rod and perpendicular to it.

$I_2$ =Moment of inertia with respect to an axis passing through one of the masses.

$I_1=\frac{mr^2}{4}+\frac{mr^2}{4}$

$I_1=\frac{2mr^2}{4}=\frac{1}{2}mr^2$

$I_2=mr^2$

$I_2>I_1$

Hence, $I_1$ is less than $I_2$

B.Less than

3 0

3 years ago

The word parallel means ____

timurjin [86]

C. Is the correct answer for this question

7 0

4 years ago

Read 2 more answers

Measuring the size of a specific object might include which of these SI units?

defon

D. Meter, Kilogram

Explanation:

There are certain units for the measurements things which are around us.
This is the SI units for the measurement of the size of the objects.
SI units are international unit systems, they are one who accepted around the world.
It is called the International System of Units, used to expresses the phenomenon happens around us in a scientific method
Here, the meter is the unit for Length in the International System of Units and Kilogram is to represent the mass of the object in SI units system.

3 0

4 years ago

What causes the disease bronchitis?

Ilia_Sergeevich [38]

Answer:

Acute bronchitis can result from: a virus, for example, a cold or flu virus. a bacterial infection. exposure to substances that irritate the lungs, such as tobacco smoke, dust, fumes, vapors, and air pollution.

Explanation:

3 0

4 years ago

An electron is projected with an initial speed vi = 4.60 × 105 m/s directly toward a very distant proton that is at rest. Becaus

frutty [35]

Answer:

$2.99\times 10^{-19}\ m$

Explanation:

<u>Given:</u>

$u$ = initial velocity of the electron = $4.60\times 10^5\ m/s$

$v$ = final velocity of the electron = $3u$

$x$ = initial position of the electron from the proton = very distant = $\infty$

<u>Assume:</u>

$m$ = mass of an electron = $9.1\times10^{-31}\ kg$

$e$ = magnitude of charge on an electron = $1.6\times10^{-19}\ C$

$p$ = magnitude of charge on an proton = $1.6\times10^{-19}\ C$

$k$ = Boltzmann constant = $9\times 10^9\ Nm^2/C^2$

$y$ = final position of the electron from the proton

$\Delta K$ = change in kinetic energy of the electron

$W$ = work done by the electrostatic force

$F$ = electrostatic force

$r$ = instantaneous distance of the electron from the proton

Let us first calculate the work done by the electrostatic force.

$W=\int Fdr\\\Rightarrow W = \int \dfrac{kep}{r^2}dr\\\Rightarrow W = kep\int \dfrac{1}{r^2}dr\\\Rightarrow W = kep\left | \dfrac{1}{r} \right |_{y}^{x}\\\Rightarrow W = kep\left ( \dfrac{1}{x}-\dfrac{1}{y} \right )\\\Rightarrow W = kep\left ( \dfrac{1}{x}-\dfrac{1}{\infty} \right )\\\Rightarrow W =\dfrac{kep}{x}$

Using the principle of the work-energy theorem,

As only the electrostatic force is assumed to act between the two charges, the kinetic energy change of the electron will be equal to the work done by the electrostatic force on the electron due to proton.

$\therefore \Delta K = W\\\Rightarrow \dfrac{1}{2}m(v^2-u^2)= \dfrac{kep}{x}\\\Rightarrow \dfrac{1}{2}m((3u)^2-u^2)= \dfrac{kep}{x}\\\Rightarrow \dfrac{1}{2}m(8u^2)= \dfrac{kep}{x}\\\Rightarrow x= \dfrac{2kep}{8mu^2}\\\Rightarrow x= \dfrac{2\times 9\times 10^9\times 1.6\times10^{-19}\times 1.6\times10^{-19}}{8\times 9.1\times10^{-31}\times (4.60\times 10^5)^2}\\\Rightarrow x=2.99\times 10^{-10}\ m\leq$

Hence, the electron is at a distance of $2.99\times 10^{-10}\ m$ when the electron instantaneously has speed of three times the initial speed.

8 0

4 years ago