The speed of the satellite moving in a stable circular orbit about the Earth is 5,916.36 m/s.
<h3>
Speed of the satellite</h3>
v = √GM/r
where;
- M is mass of Earth
- G is universal gravitation constant
- r is distance from center of Earth = Radius of earth + 4930 km
v = √[(6.626 x 10⁻¹¹ x 5.97 x 10²⁴) / ((6371 + 4930) x 10³)]
v = 5,916.36 m/s
Thus, the speed of the satellite moving in a stable circular orbit about the Earth is 5,916.36 m/s.
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Answer:
speed = 3.95 m/s
Explanation:
area = π x radius^2
area = π x (2.67 x 10^-3)^2
volume flow rate = area x speed
volume / time = area x speed
density = mass / volume
volume = mass / density
<u>mass / (density x time) = area *speed</u>
mass flow rate = mass / time
<u>mass flow rate / density = area x speed</u>
6.55 x 10^-2 / 740 = pi * (2.67 x 10^-3)^2 * speed
speed =8.8514 x 10-5 /2.2396 x 10-5 m/s
speed = 3.95 m/s
Answer:
F = 2π I R B
Explanation:
The magnetic force is described by the equation.
F = q v x B = i L x B
Where i is the current, L is a vector that points in the direction of the current (length) and B is the magnetic field.
This equation can be used in scalar form and the direction of the force found by the right hand ruler, the thumb goes in the direction of L, the fingers extended in the direction of B and the palm of the hand indicates the direction of the force if the load is positive
F = i L B sin θ
In this case the wire is in the xy plane and the z-axis field whereby they are perpendicular, θ = 90º and sin 90 = 1
F = i L B
The loop length is
L = 2π R
F = i 2π R B
F = 2π I R B
The force is in the loop
The temperature of the gas is 41.3 °C.
Answer:
The temperature of the gas is 41.3 °C.
Explanation:
So on combining the Boyle's and Charles law, we get the ideal law of gas that is PV=nRT. Here P is the pressure, V is the volume, n is the number of moles, R is gas constant and T is the temperature. The SI unit of pressure is atm. So we need to convert 1 Pa to 1 atm, that is 1 Pa = 9.86923×
atm. Thus, 171000 Pa = 1.6876 atm.
We know that the gas constant R = 0.0821 atmLMol–¹K-¹. Then the volume of the gas is given as 50 L and moles are given as 3.27 moles.
Then substituting all the values in ideal gas equation ,we get
1.6876×50=3.27×0.0821×T
Temperature = 
So the temperature is obtained to be 314.3 K. As 0°C = 273 K,
Then 314.3 K = 314.3-273 °C=41.3 °C.
Thus, the temperature is 41.3 °C.
The answer is 36 kilometers per hour, or 10 meters per second.
