It would be helpful if you can provide the chart or any additional information about the what Selma made. Anyhow, as I've searched on the internet, the answer is - Switch the stages "Evaluate the solution" and "Design a solution."
Downward force acting on the ball is 19.6N
Net force acting on the ball is 1960V N
<u>Explanation:</u>
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Given:
Mass of the ball, m = 2kg
Density of ball, σ = 800 kg/m³
Density of water, ρ = 1000 kg/m³
Downward force acting by the ball in the vessel = mg
where, g = 9.8m/s²
F = 2 X 9.8
F = 19.6N
Net force acting on the ball:
Fnet = (ρ - σ) Vg
where,
V is the volume of water
Fnet = (1000 - 800) V X 9.8
Fnet = 1960V N
If the volume is known, then substitute the value of V to find the net force.
Thus, Downward force acting on the ball is 19.6N
Net force acting on the ball is 1960V N
Answer:
Heat
Explanation:
The outer layers of the Earth are divided into the lithosphere and asthenosphere. This is based on differences inmechanical properties and in the method for the transfer of heat. Mechanically, the lithosphere is cooler and more rigid, while the asthenosphere is hotter and flows more easily. In terms of heat transfer, the lithosphere loses heat byconduction, whereas the asthenosphere also transfers heat by convection and has a nearly adiabatic temperature gradient.
Exxon Mobile, Mining Companies and anything to do with feul energy
The bead has a positive charge and so does the proton (+1.6*10⁻¹⁹ C), so they will repulse each other, sending the proton away from the bead, giving it a negative acceleration. For the magnitude, let's use Coulomb's Law: F = Kqq/r², where F is force, K is the electrostatic constant (9*10⁹ N*m²/C²), the q's are the charges and r is the distance between them. Plugging in values (remember that the nano- prefix corresponds to 10⁻⁹ and the centi- prefix is 10⁻²), we get F = (9*10⁹)*(30*10⁻⁹)(1.6*10⁻¹⁹)/(1.5*10⁻²)² = 1.92 *10⁻¹³ N. Ok, now that we have the force between the glass bead and the proton, we can use Newton's 2nd law: F = ma, where m is mass of the proton (1.67*10⁻²⁷ kg) and a is acceleration, to find the acceleration. Solving for a, a = F/m = (1.92 *10⁻¹³ N)/(1.67*10⁻²⁷ kg) = 1.15*10¹⁴ m/s².