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Gnoma [55]
2 years ago
13

PLEASE HELP ME ASAP!!!!

Chemistry
1 answer:
VashaNatasha [74]2 years ago
4 0

Answer:

16.   CsCl  =  Cs¹⁺ and Cl⁻¹

17.  CaF₂  =  Ca²⁺ and F⁻¹

18.   FeO  =  Fe²⁺ and O⁻²

19. Al₂O₃  =  Al³⁺ and O⁻²

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Neptunium-237 was the first isotope of a transuranium element to be discovered. the decay constant is /s. what is the half-life
kari74 [83]

The half-life in years of Neptunium-237 which was the first isotope is 2.1 10^{6} years.

Neptunium is most stable and Neptunium-237 is undergoes alpha decay, it means Neptunium-237 is decays by the emission of alpha particles . Seven alpha particles is emitted during decay of  Neptunium-237.  Neptunium-237 is radioactive actinide  elements and first  transuranium element.

The transuranium synthesis process involves creating a transuranium element through the transmutation process . The transmutation process  is the process of creating heavy elements from light elements. Hence the process is the transmutation of light elements. There are two types: artificial and natural transmutation.

to learn more about transuranium element.

brainly.com/question/1491386

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6 0
2 years ago
what is the volume of a sample of liquid mercury that has a mass of 76.2 g, given that the density of mercury is 13.6 g/ml?
lilavasa [31]
24 square root . i know im wrong but so what 
6 0
3 years ago
2. Suppose that 21.37 mL of NaOH is needed to titrate 10.00 mL of 0.1450 M H2SO4 solution.
AysviL [449]

Answer:

0.1357 M

Explanation:

(a) The balanced reaction is shown below as:

2NaOH+H_2SO_4\rightarrow Na_2SO_4+2H_2O

(b) Moles of H_2SO_4 can be calculated as:

Molarity=\frac{Moles\ of\ solute}{Volume\ of\ the\ solution}

Or,

Moles =Molarity \times {Volume\ of\ the\ solution}

Given :

For H_2SO_4 :

Molarity = 0.1450 M

Volume = 10.00 mL

The conversion of mL to L is shown below:

1 mL = 10⁻³ L

Thus, volume = 10×10⁻³ L

Thus, moles of H_2SO_4 :

Moles=0.1450 \times {10\times 10^{-3}}\ moles

Moles of H_2SO_4  = 0.00145 moles

From the reaction,

1 mole of H_2SO_4 react with 2 moles of NaOH

0.00145 mole of H_2SO_4 react with 2*0.00145 mole of NaOH

Moles of NaOH = 0.0029 moles

Volume = 21.37 mL = 21.37×10⁻³ L

Molarity = Moles / Volume = 0.0029 /  21.37×10⁻³  M = 0.1357 M

7 0
3 years ago
A student has 10 mL of a solution that might contain any or all of the following cations at 0.01 M concentrations: Mn2+, Ba2+, A
Ivanshal [37]
<span>For the answer to the question above,
Addition of HCl causes a precipitate to form: 
Ag+ & Cl- -- AgCl a white ppt 


H2SO4 is added to the supernate another precipitate forms: 
Ba+2 & SO4-2 --> BaSO4 a white ppt 


a solution of NaOH is added to the supernatant liquid until it is strongly alkaline. No precipitate is formed: 
no Mn+2 & no Cu+2 which would have ppt as hydroxides</span>
I hope this helps you.
7 0
2 years ago
Based on the standard EMF series and your knowledge of half-reactions, determine the cell potential and spontanei ty of a cell t
Taya2010 [7]

Answer:

+0.151, spontaneous

Explanation:

Given that;

Co^2+(aq) + 2e ---->Co(s) -0.28 V

Pb^2+(aq) + 2e ---->Pb(s). -0.13 V

Hence Co is the anode and Pb is the cathode

E°cell = E°cathode - E°anode

So;

E°cell = -0.13 V - (-0.28 V)

E°cell = 0.15 V

The cell reaction is spontaneous since E°cell is positive.

8 0
2 years ago
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