Your answer for this question is A. Electron
Answer:
See the answer below
Explanation:
<em>The correct answer would be that the solute particles lower the solvent's vapor pressure, thus requiring a higher temperature to cause boiling.</em>
Dissolving a solute particle in a solvent leads to a decrease in the vapor pressure of the solvent above the resulting solution when compared to the pure solvent. The lower the vapor pressure of a liquid, the higher the temperature required for the liquid to boil and vice versa. Hence, a higher temperature would be needed to boil a solvent with dissolved solutes.
Answer:
True
Explanation:
The percentage yield of a reaction , is given by the formula -
Percentage yield = (actual yield)/(theoretical yield) * 100
Actual yield = the exact amount of yield obtained from an experiment
Theoretical yield = the calculated yield of the experiment.
The denominator value i.e. theoretical yield can never exceed the numerator value , i.e. the actual yield ,
Hence,
percentage yield can never be more than 100% .
Knowing the two variables in this problem are volume (liter) and pressure (atm), we can determine that the law ought to be used would be Boyle's Law.
Boyle's Law: P₁v₁=P₂V₂
Using the question, we can find:
P₁ (initial pressure)=0.24 atm
V₁ (initial volume)=77.0L
P₂ (standard pressure)= 1.00atm
V₂=?
We can rearrange the equation to solve for V₂: V₂=P₁V₁/P₂
Next, we can plug in the values: V₂=
We would receive an answer of 18.48 L. However, it appears that the significant digits would be 3 as both 77.0 and 0.24 have 3 digits. As such, the answer would be 18.5L of gas at 1.00atm.
<u>Answer:</u> The molality of the solution is 0.1 m.
<u>Explanation:</u>
To calculate the molality of solution, we use the equation:
Where,
= Given mass of solute = 27.1 g
= Molar mass of solute = 27.1 g/mol
= Mass of solvent = 100 g
Putting values in above equation, we get:
Hence, the molality of the solution is 0.1 m.