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Alex73 [517]
2 years ago
6

What is oxidized in the following reaction? Na+CI —>NaCI

Chemistry
1 answer:
serious [3.7K]2 years ago
5 0

Answer:

the reducing agent is the Na ion, therefore the Na ion is oxidised. The oxidising agent is Cl ion, therefore the Cl ion is reduced.

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What conversion factors
Fantom [35]

Answer: Avogrado's number, or 6.022 x 10^23

Explanation:

To convert from moles to atoms, multiply the molar amount by Avogadro's number. To convert from atoms to moles, divide the atom amount by Avogadro's number (or multiply by its reciprocal).

7 0
3 years ago
MoO3+Al = ???<br> What are the products?
tigry1 [53]

Answer:

The electronic structures of pentacene/MoO3/Al and pentacene/Al were studied using in situ photoemission spectroscopy. The secondary electron cutoffs, highest occupied molecular orbitals (HOMOs) and core level changes were measured upon deposition of the pentacene and MoO3 to study the electronic structures at the interface.

Hope it helps!

3 0
3 years ago
How much does 0.0273 moles of Na2O weigh
devlian [24]

Answer:

1.69 g Na₂O

General Formulas and Concepts:

<u>Chemistry - Atomic Structure</u>

  • Reading a Periodic Table
  • Using Dimensional Analysis

Explanation:

<u>Step 1: Define</u>

0.0273 mol Na₂O

<u>Step 2: Identify Conversions</u>

Molar Mass of Na - 22.99 g/mol

Molar Mass of O - 16.00 g/mol

Molar Mass of Na₂O - 2(22.99) + 16.00 = 61.98 g/mol

<u>Step 3: Convert</u>

<u />0.0273 \ mol \ Na_2O(\frac{61.98 \ g \ Na_2O}{1 \ mol \ Na_2O} ) = 1.69205 g Na₂O

<u>Step 4: Check</u>

<em>We are given 3 sig figs. Follow sig fig rules and round.</em>

1.69205 g Na₂O ≈ 1.69 g Na₂O

6 0
3 years ago
What causes the jet stream? (4 points)
mamaluj [8]
The answer is A. 

Hope this helps, 

kwrob
7 0
3 years ago
A 275-mL flask contains pure helium at a pressure of 752 torr. A second flask with a volume of 475 mL contains pure argon at a p
hichkok12 [17]

Answer:

  • Partial pressure He = 276 torr
  • Partial pressure Ar = 457 torr
  • Total pressure = 733 torr

Explanation:

Assuming temperature remains constant, we can use Boyle's law to solve this problem: P₁V₁=P₂V₂.

Once the two flasks are connected and the stopock opened, the total volume is:

  • 275 + 475 = 750 mL

Now we use Boyle's law <em>twice</em>, to <u>calculate the new pressure of </u><em><u>each</u></em><u> gas</u>:

  • He ⇒ 752 torr * 275 mL = P₂He * 750 mL

P₂He = 276 torr

  • Ar ⇒ 722 torr * 475 mL = P₂Ar * 750 mL

P₂Ar = 457 torr

Finally we <u>calculate the total pressure</u>, adding the partial pressures:

  • Total pressure = P₂He + P₂Ar = 733 torr
4 0
3 years ago
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