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miv72 [106K]
3 years ago
7

Given the atomic weights of carbon, 12.01; hydrogen, 1.01; and oxygen, 16.0, what is the molar mass of glucose?

Chemistry
2 answers:
Andrews [41]3 years ago
8 0
You just multiply the atomic weight by how many mol of each element are in a mol of the molecule. 


<span>(6mol carbon * 12.01g/mol carbon) + (12 mol Hydrogen * 1.01g/mol) + (6 mol oxygen * 16.0g/mol oxygen) = 180.18 g / mol glucose.
I hope my answer helped you.</span>
Elan Coil [88]3 years ago
3 0
The molar mass of any molecule is the sum of its constituent elements atomic masses. In glucose, there are six carbon atoms, twelve hydrogen atoms, and six oxygen atoms. If we show this mathematically:
6(12.01 g/mol) + 12(1.01 g/mol) + 6(16.00 g/mol) = 180.18 grams/mole is the molar mass of glucose
The answer is C) 180.18 grams
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sample of atmospheric gas collected at an industrial site is stored in a 250 mL amber glass bottle that has a pressure of 1.02 a
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Answer:- New pressure is 0.942 atm.

Solution:- The volume of the glass bottle would remain constant here and the pressure will change with the temperature.

Pressure is directly proportional to the kelvin temperature. The equation used here is:

P_1T_2=P_2T_1

Where, T_1 and T_2 are initial and final temperatures, P_1 and P_2 are initial and final pressures.

T_1 = 20.3 + 273.15 = 293.45 K

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P_1 = 1.02 atm

T_2  = ?

Let's plug in the values in the equation and solve it for final pressure.

1.02atm(271.15K)=P_2(293.45K)

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5 0
4 years ago
A study of the decomposition reaction 3RS2  3R + 6S yields the following initial rate dat
shutvik [7]
Missing question: What is the rate constant for the reaction?
<span>[RS2](mol L-1) Rate (mol/(L·s))
0.150                0.0394
0.250                0.109
0.350                0.214
0.500                0.438</span>
Chemical reaction: 3RS₂ → 3R + 6S.
Compare second and fourth experiment, when concentration is doubled, rate of concentration is increaced by four. So rate is:
rate = k·[RS₂]².
k = 0,438 ÷ (0,500)².
k = 1,75 L/mol·s.
3 0
3 years ago
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