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4 years ago

Given the atomic weights of carbon, 12.01; hydrogen, 1.01; and oxygen, 16.0, what is the molar mass of glucose?

2 answers:

8 0

You just multiply the atomic weight by how many mol of each element are in a mol of the molecule.

<span>(6mol carbon * 12.01g/mol carbon) + (12 mol Hydrogen * 1.01g/mol) + (6 mol oxygen * 16.0g/mol oxygen) = 180.18 g / mol glucose.
I hope my answer helped you.</span>

Elan Coil [88]4 years ago

3 0

The molar mass of any molecule is the sum of its constituent elements atomic masses. In glucose, there are six carbon atoms, twelve hydrogen atoms, and six oxygen atoms. If we show this mathematically:
6(12.01 g/mol) + 12(1.01 g/mol) + 6(16.00 g/mol) = 180.18 grams/mole is the molar mass of glucose
The answer is C) 180.18 grams

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Which of the following statement is not true about cooking techniques?

nika2105 [10]

Answer:

b) Every experienced cooks at home tend not to use recipes, instead based entirely upon their knowledge of cooking technique.

Explanation:

This is because even the most experienced cooks might make a mistake, so having a recipe where they can follow is better than just use their knowledge. If his or her knowledge has a mistake it might create a big consequence.

8 0

3 years ago

What is an example in which a scientists might calculate the mean of a data set

gayaneshka [121]

An example is just when they have a a group o numbers, for any reason, and they want to find the average of then all

an example being um idk...numbers resulting from an experiment trying to find different densitys or something and they wanted to find the average density

3 0

3 years ago

17) Chlorine and Fluorine react to form gaseous chlorine trifluoride. You start with 1.75 mole of chlorine and 3.68 moles of flu

Mama L [17]

Answer:

a) $Cl_2 + 3F_2 \rightarrow 2ClF_3$

b) $F_2$ is the limiting reagent

c) Moles of $ClF_3$ produced = 2.45 mol

b) Moles of $Cl_2$ left = 1.75 -1.22 = 0.53

Explanation:

a) Balanced reaction:

$Cl_2 + 3F_2 \rightarrow 2ClF_3$

No. of mole of $Cl_2 = 1.75\ mol$

No. of mole of $F_2 = 3.68\ mol$

$Cl_2 + 3F_2 \rightarrow 2ClF_3$

As, it is clear from the reaction that,

1 mol of $Cl_2$ requires 3 moles of $F_2$

1.75 mol of $Cl_2$ require = 1.75 × 3 = 5.25 mol of $F_2$

As, only 3.68 mol of $F_2$ is present, so $F_2$ is the limiting reagent.

3 moles of $F_2$ form 2 moles of $ClF_3$

3.68 moles of $F_2$ will form = $\frac{2}{3} \times 3.68 = 2.45\ mol\ of\ ClF_3$

$Cl_2$ is present in excess.

3 moles of $F_2$ requires 1 mol of $Cl_2$

3.68 moles of $F_2$ will require = $\frac{1}{3} \times 3.68 = 1.22\ mol\ of\ Cl_2$

$Cl_2$ left = 1.75 -1.22 = 0.53 mol

6 0

4 years ago

Read 2 more answers

Pepsi [2]

Answer:

0.454moles

Explanation:

Calculate the molar mass of AgBr

Ag=108

Br=80

Molar mass= 108+80

Molar mass=188g/mol

It's mole to gram question

2moles of Na2S2O3= 188g of AgBr

X moles of Na2S2O3=42.7g of AgBr

Cross multiply

188x=2×42.7

X= 85.4/188

X=0.454moles

7 0

4 years ago

The maximum amount of copper sulfate that can be dissolved in 45.0g of water at 70C is 20.0g. what is the solubility of copper s

trasher [3.6K]

Answer:

That depends on the amount. Solubility is the maximum amount of salt dissolved in 100 g of water. So, if the amount is within limit, then yes. Solubility of anhydrous copper sulfate is 24.3 g/100 g water, so it is not bad. Put it in perspective, the solubility of NaCl is about 35 g/100 g water at room temperature. If the amount of copper sulfate is unknown, qualitative I'd say solid copper sulfate will dissolve in water completely.

Explanation:

If you use the pentahydrate CuSO4.5H2O then the solubility at 20°C is 20.8g/100ml H2O

If you use the anhydride, CuSO4. then the solubility at 20°C is 36.2g/100ml H2O

8 0

3 years ago