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4 years ago

How do you solve a chemical reaction

Chemistry

1 answer:

Setler [38]4 years ago

5 0

The chemical equation needs to be balanced so that it follows the law of conservation of mass. A balanced chemical equation occurs when the number of the different atoms of elements in the reactants side is equal to that of the products side. Balancing chemical equations is a process of trial and error.

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Write a chemical equation showing how this is an acid according to the Arrhenius definition. Express your answer as a balanced c

mylen [45]

Answer:

$HC_2H_3O_2_{(aq)}\rightarrow H^+_{(aq)}+C_2H_3O_2^-_{(aq)}$

Explanation:

Arrhenius theory:-

The Arrhenius theory was introduced introduced by Swedish scientist named Svante Arrhenius in 1887.

According to the theory, acids are the substances which dissociate in the aqueous medium to produce electrically charged atoms ( may be molecule). Out of these species furnished, one must be a proton or the hydrogen ion, $H^+$ .

So,

The expression for acid, $HC_2H_3O_2$ is:-

$HC_2H_3O_2_{(aq)}\rightarrow H^+_{(aq)}+C_2H_3O_2^-_{(aq)}$

6 0

3 years ago

Changing from liquid to gas is a chemical change.<br> True<br> False

Korolek [52]

Answer:

This is False

Explanation:

A chemical change is when the matter is completely changed.

When you have water and boil it to be a gas, it is still the same matter, just in a different form.

I hope this helps :)

6 0

3 years ago

Read 2 more answers

Trans-2-butene does not exhibit a signal in the double-bond region of the spectrum (1600–1850 cm−1); however, ir spectroscopy is

Elza [17]

However <em>trans</em>-2-Butene does not give a characteristic peak in 1620-1680 cm⁻¹ region but still the presence of carbon double bond carbon can be detected by detecting following peaks in IR Spectrum.

1) 3010-3100 cm⁻¹:
As in trans-2-Butene a hydrogen atoms ate attached to sp² hybridized carbon, therefore the stretching of =C-H (C-H) bond will give a peak of medium intensity in the range of 3010-3100 cm⁻¹.

2) 675-1000 cm⁻¹:
Another peak which is given by the bending of =C-H (C-H) bond with strong intensity will appear in the range of 675-1000 cm⁻¹.

3 0

4 years ago

The three conditions that encourage the presence of marine life in the ocean are proximity to land, water depth and ____________

Alja [10]

The answer is exposure to sunlight

7 0

3 years ago

Read 2 more answers

Student A performed gravimetric analysis for sulfate in her unknown using the same procedures we did . Results of her three tria

Andre45 [30]

Let us first calculate the accepted value of sulfate using the molar mass of sodium sulfate.

The molar mass of sodium sulfate is 2 Na + S + 4 O = 2 (22.99) + 32.07 + 4 (16)

Molar mass of Sodium sulfate = 142.05

Molar mass of sulfate = S + 4 (O) = 32.07 + 4 (16) = 96.07

% of sulfate in sodium sulfate = (Molar mass of SO4 / Molar mass of Na2SO4) x 100

% of sulfate = (96.07/142.05) x 100

% of sulfate = 67.6%

Theoretical value for % Sulfate is 67.6%

Percent error is calculated as

Percent Error = $\left | \frac{Experimental - Theoretical}{Theoretical} \right |$

Let us calculate mean for student A.

Mean for student A = (68.6 + 66.2 + 67.1) / 3 = 201.9/3 = 67.3 %

% error for student A = $\left | \frac{67.3 - 67.6}{67.6} \right |$

% error for student A = 0.44%

Mean for student B = (66.7 +66.6 + 66.5)/3 = 199.8 /3 = 66.6 %

% error for student B = $\left | \frac{66.6 - 67.6}{67.6} \right |$

% error for student B = 1.48%

Accuracy is the closeness of experimental values to the true value. This is defined in terms of absolute and percent errors.

Since percent error for student A is lower, we can say that student A was more accurate.

The precision of the data depends on the closeness of experimental values to each other. We can see that experimental values for student B were close to each other.

Therefore we can say that student B was more precise.

8 0

3 years ago