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2 years ago

NEED HELP ASAP WILL GIVE BRAINLIEST

Chemistry

1 answer:

Arlecino [84]2 years ago

7 0

Answer:

2.83

Explanation:

Molar concentration (mol/litre) = mass/molar mass × 1000/volume(in ml)

0.849 = mass/60.09 × 1000/55.5

mass = (0.849 × 60.09 × 55.5)/1000

= 2.8314

To 2 decimal places = 2.83

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How are compound, elements, and mixure different

Fofino [41]

Explanation:

Compound: a substance that is made up of more than 1 type of atom bonded together Example: H2O

Mixture: combination of two or more elements or compounds not chemicaly bonded together. example: Sugar and salt in one container

elements pure substance of an atom. Example: hydrogen

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4 years ago

What is the texture and appearance of oil

alexgriva [62]

Explanation:

yellow and slick

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4 years ago

a rectangular piece of aluminum foil measures 13.72 cm x 8.63 cm and has a mass of 3.1 g. Find how thick it is

Leona [35]

The two dimensions of aluminum foil are given 13.72 cm and 8.63 cm respectively with mass 3.1 g.

The density of aluminum is $2.7 g/cm^{3}$ . It is defined as mass per unit volume thus, volume of aluminum can be calculated as follows:

$V=\frac{m}{d}$

Putting the values.

$V=\frac{3.1 g}{2.7 g/cm^{3}}=1.148 cm^{3}$

The volume of cuboid is $l\times b\times h$ , the length and breadth are given, height can be calculated as follows;

$h=\frac{V}{l\times b}$

Putting the values,

$h=\frac{1.148 cm^{3}}{(13.72 cm)(8.63 cm)}=0.009695 cm$

Or, approximately 9.7\times 10^{-3}cm

Therefore, thickness of aluminum foil is $9.7\times 10^{-3}cm$

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3 years ago

A hydrogen atom with its electron in the n = 6 energy level emits a photon of IR light. Calculate (a) the change in energy of th

geniusboy [140]

Answer:

(a) The change in energy of the atom is --6.0528 X 10⁻²⁰ J

(b) The wavelength of the photon is 32841 Å

Explanation:

E = -kz²/n²

Where;

E is the change in the energy of the atom

k is a constant = 2.179 X 10¹⁸ J

z is the atomic number of hydrogen = 1

n = 6

E = -(1 X 2.179 X 10⁻¹⁸ )/6²

E = -6.0528 X 10⁻²⁰ J

Therefore,the change in energy of the atom is -6.0528 X 10⁻²⁰ J

(b) the wavelength (in Å) of the photon, can be calculated as follows;

E = hc/λ

λ = hc/E

where;

h is Planck's constant = 6.626 X 10⁻³⁴ js

c is the speed of light = 3 X 10⁸ m/s

λ is the wavelength of the photon

λ = (6.626 X 10⁻³⁴ X 3 X 10⁸ )/(6.0528 X 10⁻²⁰)

λ = 3.2841 X 10⁻⁶ m

λ = 32841 Å

Therefore, the wavelength of the photon is 32841 Å

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3 years ago

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il63 [147K]

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3 years ago