Question

a rectangular piece of aluminum foil measures 13.72 cm x 8.63 cm and has a mass of 3.1 g. Find how thick it is

Answer 1

The two dimensions of aluminum foil are given 13.72 cm and 8.63 cm respectively with mass  3.1 g.

The density of aluminum is $2.7 g/cm^{3}$. It is defined as mass per unit volume thus, volume of aluminum can be calculated as follows:

$V=\frac{m}{d}$

Putting the values.

$V=\frac{3.1 g}{2.7 g/cm^{3}}=1.148 cm^{3}$

The volume of cuboid is $l\times b\times h$, the length and breadth are given, height can be calculated as follows;

$h=\frac{V}{l\times b}$

Putting the values,

$h=\frac{1.148 cm^{3}}{(13.72 cm)(8.63 cm)}=0.009695 cm$

Or, approximately 9.7\times 10^{-3}cm

Therefore, thickness of aluminum foil is $9.7\times 10^{-3}cm$