Answer:
Astatine: Halogen
Nitrogen: Non-Metal
Krypton: Non-Metal, Noble Gas
Chlorine: Non-Metal
Sulfur: Non-metal
Explanation:
222 grams of calcium chloride is produced.
<h3><u>Explanation</u>:</h3>
The mole concept and the chemical equation are very much closely related with each other. In the chemical reaction, the compounds or elements in both sides are balanced according to the number of atoms of each side of the reaction. So from there we can easily find the amount of reactant reacts to produce desired product.
Here we can see that 2 moles of sodium chloride produces 1 mole of calcium chloride.
So, 4 moles of sodium chloride will produce 2 moles of calcium chloride.
Now, atomic weight of calcium =40.
Atomic weight of chlorine =35.5.
So,the molecular weight of calcium chloride = 
=111.
It means, 1 mole of calcium chloride weighs 111 grams.
So 2 moles of calcium chloride weighs 
grams = 222 grams.
Answer:
A noncompetitive inhibitor can only bind to an enzyme with or without a substrate at several places at a particular point in time
Explanation:
this is because It changes the conformation of an enzyme as well as its active site, which makes the substrate unable to bind to the enzyme effectively so that the efficiency of the enzyme decreases. A noncompetitive inhibitor binds to the enzyme away from the active site, altering/distorting the shape of the enzyme so that even if the substrate can bind, the active site functions less effectively and most of the time also the inhibitor is reversible
This is a straightforward question related to the surface energy of the droplet.
<span>You know the surface area of a sphere is 4π r² and its volume is (4/3) π r³. </span>
<span>With a diameter of 1.4 mm you have an original droplet with a radius of 0.7 mm so the surface area is roughly 6.16 mm² (0.00000616 m²) and the volume is roughly 1.438 mm³. </span>
<span>The total surface energy of the original droplet is 0.00000616 * 72 ~ 0.00044 mJ </span>
<span>The five smaller droplets need to have the same volume as the original. Therefore </span>
<span>5 V = 1.438 mm³ so the volume of one of the smaller spheres is 1.438/5 = 0.287 mm³. </span>
<span>Since this smaller volume still has the volume (4/3) π r³ then r = cube_root(0.287/(4/3) π) = cube_root(4.39) = 0.4 mm. </span>
<span>Each of the smaller droplets has a surface area of 4π r² = 2 mm² or 0.0000002 m². </span>
<span>The surface energy of the 5 smaller droplets is then 5 * 0.000002 * 72.0 = 0.00072 mJ </span>
<span>From this radius the surface energy of all smaller droplets is 0.00072 and the difference in energy is 0.00072- 0.00044 mJ = 0.00028 mJ. </span>
<span>Therefore you need roughly 0.00028 mJ or 0.28 µJ of energy to change a spherical droplet of water of diameter 1.4 mm into 5 identical smaller droplets. </span>
5 sig figs! count everything after the decimal
