The compounds will yield Positive results for the permanganate, ninhydrin, and ceric ammonium nitrate tests are
permanganate test= ethene,
ninhydrin=aspasyic acid Phenylalanine
ceric ammonium nitrate test= methanol
<h3>What is a compound?</h3>
Generally, A compound is simply defined as a substance made up of two or more different chemical elements held together by chemical bonds that are difficult to break.
In conclusion, For the permanganate test= ethene,
ninhydrin=aspasyic acid Phenylalanine
ceric ammonium nitrate test= methanol
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Answer:
- Britta paid more per kilometer driven
Explanation:
<u>1) Britta:</u>
- Distance traveled: 1,250 Km
- Gasoline price: 1.23 euros / liter
Cost per km = total cost of gasoline / distance traveled
Cost per km = gasoline used × gasoline price / distance traveled
Cost per km = 209 liter × 1.14 (euro / liter) / 1,250 km = 0.19 euro / km
<u>2) Pierce:</u>
- Distance traveled: 1,405 km
- Gasoline price = 1.23 euros / liter
Cost per km = 175 liter × 1.23 (euro / liter) / 1,405 km = 0.15 euro / km
<u>3) Comparison:</u>
- 0.19 > 0.15 ⇒ Britta paid more per kilometer driven
The ore contains 55.4% calcium phosphate (related to the mineral apatite) so the amount of Ca3(PO4)2 is 55.4%x=1000g so x=1000/0.554= 1.805kg. Now for the % of P in this amount of calcium phosphate, use all the masses of the elements in Ca3PO4= Ca=40.078 x 3= 120.23 and (PO4)2= (30.974+64)2=189.95 (NB oxygen is 16 mass x 4 =64) so the total mass is 310.2 and we have 61.95 of P (Pmass x 2) so 61.95/3102.= 0.19 or 19% P. So of the 1.805 x 0.19= 0.34kg of phosphorus.
Mass of the water : 2.23 g
<h3>Furter explanation</h3>
Heat
Q = m.c.Δt
m= mass, g
c = heat capacity, for water : 4.18 J/g° C.
ΔT = temperature
Q= 140 J
Δt = 75 - 60 = 15
mass of the water :
Answer:
(a) 0.699 kJ/K
(b) -0.671 kJ/K
(c) 0.028 kJ/K
Explanation:
The Refrigerant-134a flows into the evaporator as a saturated liquid-vapor mixture and flows out as a saturated vapor at a saturation pressure of 160 kPa and temperature of -15.64°C (estimated from the Saturated Refrigerant-134a Temperature Table).
(a) The entropy change of the refrigerant (ΔS
) = Q/T
Q = 180 kJ
T = -15.64 + 273.15 = 257.51 K
ΔS = Q/T = 180/257.51 = 0.699 kJ/K
(b) The entropy change (ΔS
) of the cooled space (ΔS) = -Q/T
Q = -180 kJ
T = -5 + 273.15 = 268.15 K
ΔS = Q/T = -180/268.15 = -0.671 kJ/K
(c) The total entropy change for this process (ΔS
) = ΔS + ΔS = 0.699 - 0.671 = 0.028 kJ/K
