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ValentinkaMS [17]
3 years ago
10

A 18.77 g sample of a compound contains 5.99 g of potassium, K, 5.43 g of chlorine, Cl, and oxygen, O. Calculate the empirical f

ormula. Insert subscripts as needed.
Chemistry
1 answer:
evablogger [386]3 years ago
7 0

The empirical formula of the compound is KClO₃.

<h3>Empirical formula </h3>

This is the simplest structural formula a compound can have.

The given mass of the elements;

potassium, K = 5.99 g

chlorine, Cl = 5.43 g

oxygen, O = 18.77 g - (5.99 + 5.43)g = 7.35 g

The empirical formula of the compound is calculated as follows;

K: \ \ \frac{5.99}{39} = 0.15 \\\\Cl: \ \ \frac{5.43}{35.5} = 0.15\\\\O: \ \ \frac{7.35}{16} = 0.46

<em>Divide through by the smallest fraction;</em>

K: \ \frac{0.15}{0.15} = 1\\\\Cl: \ \frac{0.15}{0.15} =1 \\\\O: \ \frac{0.46}{0.15} = 3

empirical formula = KClO₃

Learn more about empirical formula here: brainly.com/question/1603500

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Consider the following gas samples: 10. g of hydrogen gas, 10. g of helium gas, 2.5 moles of nitrogen gas, 110. g of carbon diox
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Explanation:

As we know ,

One mole of a gas contains 6.023 * 10 ²³ number of atoms .

Moles is denoted by given mass divided by the molecular mass ,  

Hence ,  

n = w / m

n = moles ,  

w = given mass ,  

m = molecular mass .

( a ) From the question ,

w = 10 g ,

As we know molecular mass of Hydrogen = 2 g/mol

Using the above formula , and putting the respective values ,

Moles = n ,

n = w / m  = 10 / 2 = 5 mol

The number of atoms in one molecule of Hydrogen = 2

Hence ,

The number of atoms = 5 * 2 *  6.023 * 10 ²³ = 60.23 * 10 ²³ atoms .

( b )  From the question ,

w = 10 g

As we know molecular mass of helium gas = 4 g/mol

Using the above formula , and putting the respective values ,

Moles = n ,

n = w / m  = 10 /4 = 2.5 mol

The number of atoms in one molecule of Helium = 1

Hence ,

The number of atoms = 5 * 1 *  6.023 * 10 ²³ = 30.115 * 10 ²³ atoms .

( c ) From the question ,

moles of nitrogen gas = 2.5 mol

The number of atoms in one molecule of  nitrogen gas = 2

Hence ,

The number of atoms = 2.5 * 2 *  6.023 * 10 ²³ = 30.115 * 10 ²³ atoms .

( d ) From the question ,

w = 110 g

As we know molecular mass of carbon dioxide gas = 44 g/mol

Using the above formula , and putting the respective values ,

Moles = n ,

n = w / m  = 110 / 44 = 2.5 mol

The number of atoms in one molecule of  carbon dioxide = 3

Hence ,

The number of atoms = 2.5 * 3 *  6.023 * 10 ²³ = 45.17 * 10 ²³ atoms .

( e )

From the question ,

w = 365 g

As we know molecular mass of  sulfur hexafluoride gas = 146 g/mol

Using the above formula , and putting the respective values ,

Moles = n ,

n = w / m  =  365 / 146 = 2.5 mol .

The number of atoms in one molecule of sulfur hexafluoride gas = 7

Hence ,

The number of atoms = 2.5 * 7 *  6.023 * 10 ²³ = 105.40 * 10 ²³ atoms .

Hence ,

The order is -

sulfur hexafluoride > Hydrogen > carbon dioxide  > nitrogen gas = helium gas

4 0
3 years ago
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