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daser333 [38]
4 years ago
9

Can anyone pls help I'm struggling on this question.

Mathematics
1 answer:
ankoles [38]4 years ago
6 0
It’s cube is 1.5 cm. So the answer should be 1.5 cm
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Mclaire155 THIS IS FOR YOU not and thank you
jeka57 [31]

Answer:

shhdhd

Step-by-step explanation:

Oh wow great marks

8 0
3 years ago
Read 2 more answers
What is the probability of the occurrence of a number that is odd or less than 5
yaroslaw [1]

Answer:

Hence the probability of getting a number less than 5 is 2/3.

Step-by-step explanation:

6 0
2 years ago
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Use the properties of exponents to simplify the expression: y^(y3)2
iren [92.7K]

because y^3 is raised to the power of two, we will have to multiply the exponents rather than adding them.

By distributing the power of 2, we will get y^2(6).

Because now the exponents are being multiplied, we can just add them to get y^8. The other y has a power of 1, so we'll just add the power of that y as well to get y^9.

summary:

multiply exponents if they are being raised to a power.

add exponents if they are being multiplied, and only add them if they have the same base (in this case, both the bases of the exponents are y, so we can add them)

8 0
3 years ago
Write each fraction in simplest form if the fraction is in simplest form write simplest form from 1-12
erica [24]
15. would be 1/2 because if you simplify 16/32 to 8/16 (dividing by 2 each time), then to 4/8, then 2/4, and lastly 1/2

you really dont need to do all of that because 16/32 is already 1/2 (16 is half of
32) 

16. the answer would be 7/12 because if you divide 21/36 both by 3 you get 7/12 and you cant go any more simpler.
8 0
3 years ago
Suppose that the distance of fly balls hit to the outfield (in baseball) is normally distributed with a mean of 250 feet and a s
Korvikt [17]

Answer:

On the graphing calculator, use the function normCdf, where

  • lower bound = -9999
  • upper bound = 210
  • mean = 250
  • standard deviation = 46

It will result in normCdf(-9999,210,250,46) ≈ 0.192269 or 19.2269%

6 0
3 years ago
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