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kotegsom [21]
2 years ago
5

7) Sarawong spent half of his weekly allowance on candy. To earn more money his parents let him wash the dog for $6.10. What is

his weekly allowance if he ended with $11.40?
Mathematics
1 answer:
xxMikexx [17]2 years ago
6 0

Answer:

$10.60

Step-by-step explanation:

Sarawong <em>ends</em> with $11.40, and we need to find his weekly allowance by working backward. First, we learn that he earned $6.10 of that total amount of money by washing the dog, so we can subtract the two values:

11.4 - 6.1 = 5.3

So, before washing the dog, Sarawong had $5.30. But he only received this after spending <em>half</em> of his weekly allowance, so $5.30 must be half of his weekly allowance. If we multiply $5.30 by 2, we should be able to find his weekly allownce.

5.3 × 2 = 10.6

Now, we can check our work. First, he spends half of his weekly allowance on candy. Half of 10.6 is 5.3, so he now has $5.30. Then, he earns $6.10 more by washing the dog. 5.3 + 6.1 = 11.4, which is the ending value. So, our work was correct! Hopefully that's helpful. :)

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3 years ago
Find the probability of winning a lottery by selecting the correct six integers, where the order in which these inte
stich3 [128]

The probability of winning a lottery by selecting the correct six integers, are

\begin{aligned}&(a) 1.68 \times 10^{-6} \\&(b) 5.13 \times 10^{-7} \\& (c) 1.91 \times 10^{-7} \\&(d)8.15 \times 10^{-8}\end{aligned}

<h3>What is binomial distribution?</h3>

The binomial distribution is a type of probability distribution that expresses the probability that, given a certain set of characteristics or assumptions, a value would take one of two distinct values.

Part (a); positive integers not exceeding 30.

To calculate the probability, use binomial coefficients. Pick six of the six accurate integers and none of the other twenty-four.

\frac{\left(\begin{array}{c}6 \\6\end{array}\right)\left(\begin{array}{c}24 \\0\end{array}\right)}{\left(\begin{array}{c}30 \\6\end{array}\right)}=\frac{1}{\left(\begin{array}{c}30 \\6\end{array}\right)}=1.68 \times 10^{-6}

Part (b); positive integers not exceeding 36.

To calculate the probability, use binomial coefficients. Pick six of the six accurate integers and none of the other thirty.

\frac{\left(\begin{array}{l}6 \\6\end{array}\right)\left(\begin{array}{c}30 \\0\end{array}\right)}{\left(\begin{array}{c}36 \\6\end{array}\right)}=\frac{1}{\left(\begin{array}{c}36 \\6\end{array}\right)}=5.13 \times 10^{-7}

Part (c); positive integers not exceeding 42.

To calculate the probability, use binomial coefficients. Pick six of the six accurate integers and none of the 36 other integers.

\frac{\left(\begin{array}{l}6 \\6\end{array}\right)\left(\begin{array}{c}36 \\0\end{array}\right)}{\left(\begin{array}{c}42 \\6\end{array}\right)}=\frac{1}{\left(\begin{array}{c}42 \\6\end{array}\right)}=1.91 \times 10^{-7}

Part (d); positive integers not exceeding 48.

To calculate the probability, use binomial coefficients. Choose six of the six accurate integers and none of the other 42.

\frac{\left(\begin{array}{l}6 \\6\end{array}\right)\left(\begin{array}{c}42 \\0\end{array}\right)}{\left(\begin{array}{c}48 \\6\end{array}\right)}=\frac{1}{\left(\begin{array}{c}48 \\6\end{array}\right)}=8.15 \times 10^{-8}

To know more about binomial probability, here

brainly.com/question/9325204

#SPJ4

The complete question is-

Find the probability of winning a lottery by selecting the correct six integers, where the order in which these integers are selected does not matter, from the positive integers not exceeding a) 30. b) 36. c) 42. d) 48.

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2 years ago
What is 1/10of 300 in a math equation
zhenek [66]
1/10 = 10/100
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Effectus [21]
Distributive property first so you wanna do 2•4 then you will get 8x then you have to do 2•8 Wich is 16 then you will end up with 8x-16+16t=48 move the expression to the right 8x=48+16-16t 8x=64-16t x=8-2t?
8 0
3 years ago
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