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Sindrei [870]
3 years ago
5

I WILL GIVE BRAINLEIST

Mathematics
1 answer:
soldi70 [24.7K]3 years ago
3 0

Answer: x = 1, y = 1

Step-by-step explanation:

Step 1: Solve for x

Multiply bottom equation by 2.

5x + 2y = 7

2(3x – y = 2)

___________

5x + 2y = 7

+ 6x - 2y = 4

___________

11x =  11    divide each side by 11      x = 1

Step 2: Solve for y

Substitute x=1 into any equation. We will do equation 1.

5x + 2y =  7    5*1 + 2y = 7

5 + 2y = 7  

subtract 5 from each side.

2y = 2  divide each side by 2

y = 1

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Step-by-step explanation:

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Answer:

Option (b) is correct.

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Step-by-step explanation:

Given:Expression \sqrt{x^2y^3}+2\sqrt{x^3y^4}+xy\sqrt{y}

We have to find the sum of the given expression and choose the correct from the given options.

Consider the given expression  \sqrt{x^2y^3}+2\sqrt{x^3y^4}+xy\sqrt{y}.

\sqrt{x^2y^3} can be written as \sqrt{x^2y^2y}=xy\sqrt{y}

Also, 2\sqrt{x^3y^4} can be written as 2\sqrt{x^3y^4}=2\sqrt{x^2x(y^2)^2}=2xy^2\sqrt{x}

Now, the given expression becomes,

\sqrt{x^2y^3}+2\sqrt{x^3y^4}+xy\sqrt{y}

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=2xy\sqrt{y}+2xy^2\sqrt{x}.

Thus, The sum of given expression  \sqrt{x^2y^3}+2\sqrt{x^3y^4}+xy\sqrt{y} is  2xy\sqrt{y}+2xy^2\sqrt{x}

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