How do you solve y= -3+3

Which equation can be used to solve for x, the increase in<br> side length of the square in inches?

MrRa [10]

Is there any picture to go along?

6 0

3 years ago

The prostate-specific antigen (PSA) test is a simple blood test to screen for prostate cancer. It has been used in men over 50 a

Ugo [173]

The question is incomplete. I am writing the complete question below:

The prostate-specific antigen (PSA) test is a simple blood test to screen for prostate cancer. It has been used in men over 50 as a routine part of a physical exam, with levels above 4 ng/mL indicating possible prostate cancer. The test result is not always correct, sometimes indicating prostate cancer when it is not present and often missing prostate cancer that is present. Suppose that these are the approximate conditional probabilities of a positive (above 4 ng/ml) and negative test result given cancer is present or absent.

Positive Result Negative Result

Cancer Present 0.21 0.79

Cancer Absent 0.06 0.94

In a large study of prostate cancer screening, it was found that about 6.6% of the population has prostate cancer.

What is the probability that the test is positive for a randomly chosen person from this population? (Enter your answer to five decimal places.)

P(Positive test) =

Answer:

P(Positive Result) = 0.0699

Step-by-step explanation:

We are given that 6.6% of the population has prostate cancer. So,

P(Cancer Present) = 0.066

P(Cancer Absent) = 1 - 0.066 = 0.934

From the given conditional probability table, we have:

P(Positive Result | Cancer Present) = 0.21

P(Positive Result | Cancer Absent) = 0.06

We need to find the probability that the result is positive. It can be either that the result is positive and cancer is present or the result is positive and the cancer is absent. So,

P(Positive Result) = P(Positive Result∩Cancer Present) + P(Positive Result∩Cancer Absent)

= P(Positive Result | Cancer Present)*P(Cancer Present) + P(Positive Result | Cancer Absent)*P(Cancer Absent)

= (0.21)*(0.066) + (0.06)*(0.934)

= 0.01386 + 0.05604

P(Positive Result) = 0.0699

5 0

4 years ago

(20 POINTS AND BRAINLIEST FOR BEST)

Lena [83]

Answer:

i used be so good at this now i suck because it's been awhile

Step-by-step explanation:

7 0

3 years ago

answer to #10 and #13. can’t figure out how to use interval notation to write domain and range for graphs.

Lyrx [107]

Interval notation is used to write a set of real numbers from one value to another value.
On the left, you start with left parenthesis or left bracket.
Then you follow by two numbers separated by a comma.
You then finish with a right parenthesis or right bracket.
To include a number, use a square bracket.
To exclude a number use parenthesis.
To write the set of numbers, you need to list the smallest number in the set followed by the largest number in the set. An interval is always stated with two numbers, from the smallest in the set to the largest in the set. The numbers are always separated by a comma.

Examples:

1) All numbers from 6 to 10, including 6 and 10.
Algebra: 6 <= x <= 10
Interval: [6, 10]
Notice brackets since both 6 and 10 are included in this interval.

2) All number from 5 to 20, including 5 but not including 20.
Algebra 5 <= x < 20
Interval: [5, 20)
Bracket with 5 means include 5. Parenthesis with 20 means 20 is not included.

3) All numbers greater than or equal to 7.
Algebra: x >= 7
Interval: [7, ∞)
The 7 has a bracket because it is included. Infinity always has parenthesis.
With the infinity symbol, always use parenthesis, not square bracket.

4) All numbers less than -5.
Algebra: x < - 5
Interval: (-∞, 5)

Now for your problems.

10.
This is a line. Both the domain and range all all real numbers.
That means the interval is from negative infinity to positive infinity.
(-∞, ∞)
Both the domain and range are that same interval, all real numbers, from negative infinity to positive infinity.

13.
The domain is all real numbers as you can see the x-coordinates extend left forever and right forever. The domain is the same interval as the domain and range of problem 10.

The range is zero and all positive numbers.
You can think of it a all values of y such that y is greater than or equal to zero. Notice that zero is included in the interval.

[0, ∞)

Since zero is included, we use a left bracket, not left parenthesis.
With infinity, we alyways use parentheses, not brackets.

8 0

3 years ago

3) Y-3=4(n=2)<br>*to draw graph

Kazeer [188]

Answer:

[see below]

Step-by-step explanation:

I am assuming that you mean: $y-3=4(x-2)$ .

The equation is in point slope form...

$y-y_1=m(x-x_1)$

The point used in the equation is (2, 3). 2 replaces 'x1' and 3 replaces 'y1'.

If you convert the equation in to slope intercept form:

$y-3=4(x-2)\\\\y-3=4x-8\\\\y-3+3=4x-8+3\\\\\boxed{y=4x-5}$

You get -5 as the y-intercept.

So, the line you draw would pass through points (2,3) and (0,-5).

Hope this helps.

3 0

4 years ago

How do you solve y= -3+3​

How do you solve y= -3+3