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klio [65]
3 years ago
6

Harmonics problem. A square wave of frequency f contains harmonics (sine waves) at f, 3f, 5f, 7f, ... . Suppose a system respond

s to frequencies in the range 20-40 kHz but is insensitive outside of this range.EXAMPLE:Imagine applying a square wave with f = 30 kHz to this system. What is the shape of the response?[Answer: a 30 kHz sine wave. ]Imagine applying a square wave with f = 10 kHz to this system.What is the shape of the response?A. A 10 kHz sine waveB. A combination of 20, 30 and 40 kHz sine wavesC. A 30 kHz sine waveD. No response
Physics
1 answer:
ira [324]3 years ago
4 0

Answer:

B

Explanation:

A square of frequency of consists of the infinite sum of sine waves, whose frequencies are the odd multiples of the main frequency f i.e f, 3f,5f, 7f, ... . Given that the range of frequencies, to which the system responds is 20-40 kHz, for a square wave of frequency 10kHz we need to look for the harmonics whose frequencies are in the systems' respond range, which are the  harmonics of 20, 30 and 40 kHz

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Acceleration = (change in speed) / (time for the change)

Change in speed = (speed at the end) minus (speed at the beginning)

Change in speed = (-58 m/s) minus (54 m/s)

Change on speed = -112 m/s

Acceleration = (-112 m/s) / (0.8 s)

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3 years ago
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Certain suv ads claim that their vehicles can climb a slope of 45?. what is the minimum coefficient of static friction between t
kotykmax [81]
First, you make a force body diagram to illustrate the problem. Then, apply Newton's laws of motion.

Summation of forces along the y-direction:

F = 0 (bodies at equilibrium) = Normal force - weight*cos45 = 0
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Summation of forcesalong the x-direction:

F = 0 (bodies at equilibrium) = Frictional force - weight*sin45 = 0
x*Normal force - weight*sin45 = 0   (let x be the min coeff of static friction)
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x = sin45/cos45 = 1

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8 0
3 years ago
Please, Help!!
Elenna [48]

Let, 1st force = a

2nd force = b

A.T.Q,

a+b = 10

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3 years ago
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Part A
Gemiola [76]

The Mass of the barter and the ball is 3.1kg

Data Given;

  • F = 1.1*10^-9N
  • r = 0.76m
  • G = 6.67*10^-11 m^3 kg^-1 s^-1

Assuming the barter and the ball have equal mass, we can apply gravitational force formula.

<h3>Gravitational Force</h3>

F = \frac{Gm_1m_2}{r^2}

This is product of the mass of the two bodies and divided by the square of their distance apart.

Substituting the values into the formula

F = \frac{Gm_1m_2}{r^2\\}\\m_1 = m_2 = m\\1.1*10^-^9=\frac{6.67*10^-^1^1*m^2}{0.76^2}  \\m^2 = \frac{1.1*10^-^9*0.76^2}{6.67*10^-^1^1} \\m^2 = 9.525\\m = \sqrt{9.525}\\m =3.086=3.1kg

From the calculations above, the mass of the barter and the ball is 3.1kg

Learn more on gravitational force here;

brainly.com/question/11359658

8 0
3 years ago
A motor does 3,441 joules of work in 13.66 seconds. What is the power of the motor?
il63 [147K]

Answer:

Power = 251.9 Watts

Explanation:

Power = Work Done / Time taken

Power = 3441 / 13.66

Power = 251.9 Joule / Second

Power = 251.9 Watts

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3 years ago
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