Answer:
Inertia
Explanation:
Inertia is the property that any physical object has of remaining in its state of relative motion. Therefore, it is the resistance that opposes matter to modify its state of motion, which includes changes in speed or changes in the direction of movement.
Answer:
Approximately 0.0898 W/m².
Explanation:
The intensity of light measures the power that the light delivers per unit area.
The source in this question delivers a constant power of
. If the source here is a point source, that
of power will be spread out evenly over a spherical surface that is centered at the point source. In this case, the radius of the surface will be 9.6 meters.
The surface area of a sphere of radius
is equal to
. For the imaginary 9.6-meter sphere here, the surface area will be:
.
That
power is spread out evenly over this 9.6-meter sphere. The power delivered per unit area will be:
.
Answer:
physical
Explanation:
how thick something is is a physical trait, so it's a physical property!
Answer:
P = 180.81 J
Explanation:
Given that,
Mass of a object, m = 4.1 kg
It is lifted to a height of 4.5 m
We need to find the potential energy of the object due to gravity. It is given by the formula as follows :
P = mgh Where g is acceleration due to gravity
P = 4.1 kg × 9.8 m/s² × 4.5 m
P = 180.81 J
Hence, the potential energy is 180.81 J.
Answer:
<em>The final speed of the second package is twice as much as the final speed of the first package.</em>
Explanation:
<u>Free Fall Motion</u>
If an object is dropped in the air, it starts a vertical movement with an acceleration equal to g=9.8 m/s^2. The speed of the object after a time t is:

And the distance traveled downwards is:

If we know the height at which the object was dropped, we can calculate the time it takes to reach the ground by solving the last equation for t:

Replacing into the first equation:

Rationalizing:

Let's call v1 the final speed of the package dropped from a height H. Thus:

Let v2 be the final speed of the package dropped from a height 4H. Thus:

Taking out the square root of 4:

Dividing v2/v1 we can compare the final speeds:

Simplifying:

The final speed of the second package is twice as much as the final speed of the first package.