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lesya692 [45]
3 years ago
10

A particle's position is given by x = 4.0t2 - 32t + 36, with x in meters and time t in seconds. At what position does the partic

le come to a momentary stop, to reverse its motion?
Physics
1 answer:
daser333 [38]3 years ago
8 0
Firstly, we must find the equation the speed, it can be obtained by the derivative of x =<span>x = 4.0t2 - 32t + 36, it means v= 8.0t-32. the particule stops means v= 0, and 0= 8.0t-32, which implies 8t=32, so t=4s, and then x(t=4) = 4.0(4)^2 - 32(4) + 36= - 28m
so x = - 28 m</span>
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