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BARSIC [14]
3 years ago
15

Which of the following substances is a compound?

Physics
2 answers:
EleoNora [17]3 years ago
8 0

Answer:

D. hydrogen sulfide gas (H2S)

Explanation:

A compound is composed of two or more elements chemically bound together.

In this case, hydrogen is chemically bounded with sulfur to form a gaseous compound called hydrogen sulfide.

Read more on Brainly.com - brainly.com/question/12615069#readmore

Explanation:

Dima020 [189]3 years ago
7 0

Answer:

D. hydrogen sulfide gas (H2S)

Explanation:

A compound is composed of two or more elements chemically bound together.

In this case, hydrogen is chemically bounded with sulfur to form a gaseous compound called hydrogen sulfide.

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A firecracker breaks up into two pieces , one has a mass of 200 g and files off along the x –axis with a speed of 82.0 m/s and t
Readme [11.4K]

Answer:

A) 21.2 kg.m/s at 39.5 degrees from the x-axis

Explanation:

Mass of the smaller piece = 200g = 200/1000 = 0.2 kg

Mass of the bigger piece = 300g = 300/1000 = 0.3 kg

Velocity of the small piece = 82 m/s

Velocity of the bigger piece = 45 m/s

Final momentum of smaller piece = 0.2 × 82 = 16.4 kg.m/s

Final momentum of bigger piece = 0.3 × 45 = 13.5 kg.m/s

since they acted at 90oc to each other (x and y axis) and also momentum is vector quantity; then we can use Pythagoras theorems

Resultant momentum² = 16.4² + 13.5² = 451.21

Resultant momentum = √451.21 = 21.2 kg.m/s at angle 39.5 degrees to the x-axis  ( tan^-1 (13.5 / 16.4)

5 0
3 years ago
The ability of matter to easily combine chemically with other substances is know as?
skelet666 [1.2K]
Reactivity is the ability of matter that allows it to easily chemically combine with other substances.
4 0
3 years ago
Read 2 more answers
A 51.0 kg cheetah accelerates from rest to its top speed of 31.7 m/s. HINT (a) How much net work (in J) is required for the chee
andrey2020 [161]

(a) 2.56\cdot 10^4 J

The work-energy theorem states that the work done on the cheetah is equal to its change in kinetic energy:

W= \Delta K = \frac{1}{2}mv^2 - \frac{1}{2}mu^2

where

m = 51.0 kg is the mass of the cheetah

u = 0 is the initial speed of the cheetah (zero because it starts from rest)

u = 31.7 m/s is the final speed

Substituting, we find

W=\frac{1}{2}(51.0 kg)(31.7 m/s)^2 - \frac{1}{2}(51.0 kg)(0)^2=2.56\cdot 10^4 J

(b) 6.1 cal

The conversion between calories and Joules is

1 cal = 4186 J

Here the energy the cheetah needs is

E=2.56\cdot 10^4 J

Therefore we can set up a simple proportion

1 cal : 4186 J = x : 2.56\cdot 10^4 J

to find the equivalent energy in calories:

x=\frac{(1 cal)(2.56\cdot 10^4 J)}{4186 J}=6.1 cal

3 0
3 years ago
What is the electric field due to a point charge of 20uC at a distance of 1 meter away from it?
Anettt [7]

The electric field due to a point charge of 20uC at a distance of 1 meter away from it is 180000 \frac{N}{C}.

First, you have to know that the space surrounding a load suffers some kind of disturbance, since a load located in that space will suffer a force. The disturbance that this charge creates around it is called an electric field.

In other words, an electric field exists in a certain region of space if, when introducing a charge called witness charge or test charge, it undergoes the action of an electric force.

The electric field E created by the point charge q at any point P, located at a distance r, is defined as:

E=K\frac{q}{r^{2} }

where K is the constant of Coulomb's law.

In this case, you know:

  • K= 9×10⁹\frac{Nm^{2} }{C^{2} }
  • q= 20 uC=20×10⁻⁶ C
  • r= 1 m

Replacing in the definition of electric field:

E=9x10^{9} \frac{Nm^{2} }{C^{2} }\frac{20x10^{-6} C}{(1 m)^{2} }

Solving:

<u><em>E=180000 </em></u>\frac{N}{C}<u><em /></u>

Finally, the electric field due to a point charge of 20uC at a distance of 1 meter away from it is 180000 \frac{N}{C}.

Learn more:

  • <u>brainly.com/question/1658733?referrer=searchResults</u>
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  • <u>brainly.com/question/14472528?referrer=searchResults</u>
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5 0
2 years ago
juan aims his boat directly across a river flowing at 8mi/hr. juan's boat travels at 6 miles/hr in still water. how was does jua
son4ous [18]
6mph:

Suppose the boat is traveling on a y axis. The river flow acts on the x axis. Motion on each axes are independent. The linear speed of the boat is not changed. Furthermore the projectile motion is changing, but you're specifically asking about the linear speed of the boat which is unchanged.
4 0
3 years ago
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