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vampirchik [111]
4 years ago
8

Some birds migrate 20,000 miles. If 1 mile equals 1.6 kilometers, calculate the distance these birds fly in kilometers.

Physics
2 answers:
ale4655 [162]4 years ago
7 0
32,000 because 1.6 times 20,000 is 32,000

faust18 [17]4 years ago
6 0
Set up a proportion

1 mile/1.6 km = 20,000miles/x

Cross Multiply
x = (20,000) * (1.6)
x = 32,000 kilometers
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E = 0,39 + 0,59 = 0,98 J

Explanation:

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A player cathces a ball. Consider the action force to be the impact of the ball against the players glove. What is the reaction
Anuta_ua [19.1K]

Force the glove exerts on the ball

Explanation:

The reaction to this force is the force the glove exerts on the ball.

According to Newton's third ;aw of motion "Action and reaction forces are equal and opposite in direction".

  • The action force is the impact of the ball against the players glove.
  • The reactive force is the force the glove exerts on the ball.

This reactive force is directed in the opposite direction and it is the reason why the motion of the incoming ball is halted.

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3 years ago
A tall cylinder contains 25 cm of water. Oil is carefully poured into the cylinder, where it floats on top of the water, until t
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Answer: 377.3\ kPa

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After oil is poured, the total height becomes h'=40\ cm

Pressure at the bottom will be the sum due to the water and oil column

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Pressure at the bottom

\Rightarrow P=10^3\times g\times 25+900\times g\times 15\\\Rightarrow P=100g[250+135]\\\Rightarrow P=3773\times 100\ Pa\\\Rightarrow P=377.3\ kPa

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Why is it easier to change meters to centimeters than it is changing yards to feet?
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3 years ago
A 0.23-f capacitor is desired. What area must the plates have if they are to be separated by a 3.8-mm air gap?
tia_tia [17]

The area of the plates must have is(A)= 9.91×10⁷ m²

<h3 /><h3>How can we calculate the value of a area of a capacitor?</h3>

To calculate the the value of a area of the plates of a capacitor, we are using the formula,

C=\frac{\epsilon_0 A}{d}

Or, A= \frac{C\times d}{\epsilon_0}

Here we are given,

C= The desired capacitance of a capacitor.

= 0.23F

d=distance of separation between the plates.

=3.8mm= 0.0038m.

\epsilon_0= permittivity of the vacuum.  

=8.854×10⁻¹²F/m

We have to calculate the area of the plates must have = A m².

Now we put the known values in the above equation, we can get

A= \frac{C\times d}{\epsilon_0}

Or, A=\frac{0.23\times 0.0038}{8.854\times 10^{-12}}

Or, A= 9.91×10⁷ m²

From the above calculation, we can conclude that the area of the plates must have is(A)= 9.91×10⁷m²

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