There are a couple of ways you can go at this. One way is to look at the price multipliers. For a markdown of d, the price is multiplied by 1-d. For a markup of u, the price is multiplied by 1+u. Your original price is multiplied by ...
35% markdown: (1 - 0.35) = 0.65
25% markdown: (1 - 0.25) = 0.75
18% markup: (1 + 0.18) = 1.18
15% markdown: (1 - 0.15) = 0.85
The product of all these multipliers is
0.65×0.75×1.18×0.85 = 0.4889625
As you note, $5600×0.4889625 = $2738.19.
Since this multiplier is 1-d, we can find d as
1 - d = 0.4889625
d = 1 - 0.4889625 = 0.5110375
The markdown percentage is this number times 100%:
markdown% ≈ 51.1%
_____
Alternatively, you can work with your final value to find the percentage change from the original.
percent change = ((final value) - (original value))/(original value) × 100%
= (2738.19 - 5600)/5600 × 100%
= -2861.81/5600 × 100%
= -0.5110375 × 100% . . . . . . . this should look familiar
percent change ≈ -51.1%
When the change is negative, it is a markdown (not a markup).
The markdown is 51.1%.
<u>Assuming that you want the product of the two factors given in each problem</u>:
⇒ we solve this problem by timing each unit of a factor to every unit
of the other factor
⇒then add each one of them who shares a common like-term
⇒to get the answer
<u>Let's solve:</u>
![(4m+n)(m-2n)=4m*m+(-2n)*4m+n*m+n(-2n)\\=4m^2-7nm-2n^2](https://tex.z-dn.net/?f=%284m%2Bn%29%28m-2n%29%3D4m%2Am%2B%28-2n%29%2A4m%2Bn%2Am%2Bn%28-2n%29%5C%5C%3D4m%5E2-7nm-2n%5E2)
![(2a-4b)(7a-2b)=2a*7a+(-2b)(2a)+(-4b)7a+(-4b)(-2b)\\=14a^2-4ab-28ab+8b^2\\=14a^2-32ab+8b^2](https://tex.z-dn.net/?f=%282a-4b%29%287a-2b%29%3D2a%2A7a%2B%28-2b%29%282a%29%2B%28-4b%297a%2B%28-4b%29%28-2b%29%5C%5C%3D14a%5E2-4ab-28ab%2B8b%5E2%5C%5C%3D14a%5E2-32ab%2B8b%5E2)
![(4m+1)^2=(4m+1)(4m+1)=4m*4m+4m*1+1*4m+1\\=16m^2+4m+4m+1\\=16m^2+8m+1](https://tex.z-dn.net/?f=%284m%2B1%29%5E2%3D%284m%2B1%29%284m%2B1%29%3D4m%2A4m%2B4m%2A1%2B1%2A4m%2B1%5C%5C%3D16m%5E2%2B4m%2B4m%2B1%5C%5C%3D16m%5E2%2B8m%2B1)
![(2w+1)(2w-1)=2w*2w+2w(-1)+1*(2w)+1(-1)\\=4w^2-1](https://tex.z-dn.net/?f=%282w%2B1%29%282w-1%29%3D2w%2A2w%2B2w%28-1%29%2B1%2A%282w%29%2B1%28-1%29%5C%5C%3D4w%5E2-1)
![(m+3)(m^2+4m+7)\\=m*m^2+m*4m+m*7+3m^2+3*4m+3*7\\=m^3+4m^2+7m+3m^2+12m+21\\=m^3+7m^2+19m+21](https://tex.z-dn.net/?f=%28m%2B3%29%28m%5E2%2B4m%2B7%29%5C%5C%3Dm%2Am%5E2%2Bm%2A4m%2Bm%2A7%2B3m%5E2%2B3%2A4m%2B3%2A7%5C%5C%3Dm%5E3%2B4m%5E2%2B7m%2B3m%5E2%2B12m%2B21%5C%5C%3Dm%5E3%2B7m%5E2%2B19m%2B21)
![(3x+2)(5x^2-12x-2)\\=3x*5x^2+3x(-12x)+3x(-2)+2(5x^2)+2(-12x)+2(-2)\\=15x^3-36x^2-6x+10x^2-24x-4\\=15x^3-26x^2-30x-4](https://tex.z-dn.net/?f=%283x%2B2%29%285x%5E2-12x-2%29%5C%5C%3D3x%2A5x%5E2%2B3x%28-12x%29%2B3x%28-2%29%2B2%285x%5E2%29%2B2%28-12x%29%2B2%28-2%29%5C%5C%3D15x%5E3-36x%5E2-6x%2B10x%5E2-24x-4%5C%5C%3D15x%5E3-26x%5E2-30x-4)
Hope that helps!
Answer:
y![\sqrt{5}](https://tex.z-dn.net/?f=%5Csqrt%7B5%7D)
Step-by-step explanation:
Like radicals are radicals that have the same radical (the number into the square root) and the same radicand (the number above the root)
Here, only the last expression
can be chosen.