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Feliz [49]
3 years ago
7

What is the fifth term in the expansion of (3x - 3y)7? __ x3y4

Mathematics
2 answers:
olga2289 [7]3 years ago
7 0
(r+1)th term of (a +x)^n = nCr a^(n-r)x^r

so 5th term of (3x - 3y)^7  = 7C4 * (3x)^(7-4) (-3y)^4      (NOTE r = 4)

=   35 * 27x^3 * 81y^4

=  76545 x^4y^3
Dafna11 [192]3 years ago
5 0

Answer: 76545


Step-by-step explanation: That is what you need to enter on edge


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-17=x-15<br> I'm stuck so can someone help
Strike441 [17]

Answer:

-2

Step-by-step explanation:

-2-15

-2 +(-15)

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sergiy2304 [10]
F(x)/g(x) = (2x +3)(x -1)/(x -1) = 2x +3 . . . . . x ≠ 1

The domain of (f/g)(x) is all real numbers except 1.

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3 years ago
Please help me with those question please help with out number 1
alina1380 [7]

Answer:

1) For each value of x, a value of y is increased by 5.

x = 0, y = 5

x = 1, y = 10

x = 2, y = 15

x = 3, y = 20

------------------------------------------------------------------------------------------

2) For each two values of x, a value of y is increased by 10.

x = 0, y = -2

x = 2, y = 8

x = 4, y = 18

x = 6, y = 28

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3)

x = 0, y = 1

x = 1, y = \frac{7}{5}

x = 5, y = 3

x = 10, y = 5

-------------------------------------------------------------------------------------------------

4)

x = 0, y = 2

x = 1, y = 17

x = 2, y = 32

x = 5, y = 77

Step-by-step explanation:

This is as easy as replacing x for the actual value show on the table.

1)

y=5x+5

When x = 0, y = ?

y=5(0)+5\\y=0+5\\y=5

When x = 1, y = ?

y=5(1)+5\\y=5+5\\y=10

When x = 2, y = ?

y=5(2)+5\\y=10+5\\y=15

When x = 3, y = ?

y=5(3)+5\\y=15+5\\y=20

-------------------------------------------------------------------------------------------------------

2)

y=5x-2

When x = 0, y = ?

y=5(0)-2\\y=0-2\\y=-2

When x = 2, y = ?

y=5(2)-2\\y=10-2\\y=8

When x = 4, y = ?

y=5(4)-2\\y=20-2\\y=18

When x = 6, y = ?

y=5(6)-2\\y=30-2\\y=28

----------------------------------------------------------------------------------------------------

3)

y=\frac{2}{5}x +1

When x = 0, y = ?

y=\frac{2}{5}(0) +1

y=0 +1\\y=1

When x = 1, y = ?

y=\frac{2}{5}(1) +1\\y=\frac{2}{5} +1

y=\frac{2}{5}+1(\frac{5}{5})\\ y=\frac{2}{5}+\frac{5}{5}  \\y=\frac{7}{5}

When x = 5, y = ?

y=\frac{2}{5}(5) +1\\y=2+1\\y=3

When x = 10, y = ?

y=\frac{2}{5}(10) +1\\y=2(2) +1\\y=4+1\\y=5

-------------------------------------------------------------------------------------------------

4)

y=15x+2

When x = 0, y = ?

y=15(0)+2\\y=0+2\\y=2

When x = 1, y = ?

y=15(1)+2\\y=15+2\\y=17

When x = 2, y = ?

y=15(2)+2\\y=30+2\\y=32

When x = 5, y = ?

y=15(5)+2\\y=75+2\\y=77

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