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What is the slope-intercept equation of the line whose y-intercept is<br> 8 with slope -5?

ira [324]

Answer:

y = - 5x + 8

Step-by-step explanation:

Given that :

Intercept = 8

Slope = - 5

Recall, the general. Slope - intercept equation :

y = bx + c

Where;

b = slope ; c = intercept

Plugging the Given slope and intercept values, equation becomes ;

y = - 5x + 8

3 0

3 years ago

Find the volume and surface area of the prism below

Nata [24]

Answer:

a) The volume of the prism is 660 mm³

b) The surface area of the prism is 514 mm²

Step-by-step explanation:

The given prism for which we are to find the volume and the surface area shows the dimensions of the sides

a) To find the volume, we can consider the prism as a composite figure as follows;

The topmost cuboid with dimensions (15 - 2×3) mm, 3 mm, and 9 mm

Therefore, the volume of the topmost cuboid, V₁, is given as follows;

V₁ = 5 mm × 3 mm × 9 mm = 135 mm³

The volume of the cuboid on which the top cuboid rest, V₂, is given as follows;

V₂ = 15 mm × 5 mm × 7 mm = 525 mm³

The volume of the prism, V = V₁ + V₂

Therefore, we have;

V =135 mm³ + 525 mm³ = 660 mm³

The volume of the prism, V = 660 mm³

b) The surface area of the prism is given as follows;

The surface area of the top cuboid, SA₁, is given as follows;

SA₁ = 9 mm × 5 mm + 2 × 3 mm × 9 mm + 2 × 3 mm × 5 mm = 129 mm²

The surface area of the larger cuboid, SA₂, is given as follows;

SA₂ = 2 × 15 mm × 7 mm + 2 × 5 mm × 7 mm + 2 × 3 mm × 5 mm + 15 mm × 5 mm = 385 mm²

The surface area of the prism, SA = SA₁ + SA₂

∴ The surface area of the prism, SA = 129 mm² + 385 mm² = 514 mm²

4 0

3 years ago

It takes Earth about 365 days to orbit the Sun. It takes Uranus about 85 times as long. Write a numerical expression to describe

steposvetlana [31]

U=days of Uranus Orbit
365x85=U

3 0

4 years ago

Twice a number deceased by 7.translate in algebraic expressions

Dafna1 [17]

Twice a number (2x) decreased by 7 (- 7).

2x - 7

Two times a specfic number (x) subtracted by 7.

8 0

3 years ago

Read 2 more answers

A right circular cylinder is inscribed in a sphere with diameter 4cm as shown. If the cylinder is open at both ends, find the la

SOVA2 [1]

Answer:

$8\pi\text{ square cm}$

Step-by-step explanation:

Since, we know that,

The surface area of a cylinder having both ends in both sides,

$S=2\pi rh$

Where,

r = radius,

h = height,

Given,

Diameter of the sphere = 4 cm,

So, by using Pythagoras theorem,

$4^2 = (2r)^2 + h^2$ ( see in the below diagram ),

$16 = 4r^2 + h^2$

$16 - 4r^2 = h^2$

$\implies h=\sqrt{16-4r^2}$

Thus, the surface area of the cylinder,

$S=2\pi r(\sqrt{16-4r^2})$

Differentiating with respect to r,

$\frac{dS}{dr}=2\pi(r\times \frac{1}{2\sqrt{16-4r^2}}\times -8r + \sqrt{16-4r^2})$

$=2\pi(\frac{-4r^2+16-4r^2}{\sqrt{16-4r^2}})$

$=2\pi(\frac{-8r^2+16}{\sqrt{16-4r^2}})$

Again differentiating with respect to r,

$\frac{d^2S}{dt^2}=2\pi(\frac{\sqrt{16-4r^2}\times -16r + (-8r^2+16)\times \frac{1}{2\sqrt{16-4r^2}}\times -8r}{16-4r^2})$

For maximum or minimum,

$\frac{dS}{dt}=0$

$2\pi(\frac{-8r^2+16}{\sqrt{16-4r^2}})=0$

$-8r^2 + 16 = 0$

$8r^2 = 16$

$r^2 = 2$

$\implies r = \sqrt{2}$

Since, for r = √2,

$\frac{d^2S}{dt^2}=negative$

Hence, the surface area is maximum if r = √2,

And, maximum surface area,

$S = 2\pi (\sqrt{2})(\sqrt{16-8})$

$=2\pi (\sqrt{2})(\sqrt{8})$

$=2\pi \sqrt{16}$

$=8\pi\text{ square cm}$

4 0

3 years ago

PLEASE IM LITERALLY BEGGING I WILL MARK U THE BRAINLEIST OR WHATEVER JUSY HELP I NEED TO PASS​

PLEASE IM LITERALLY BEGGING I WILL MARK U THE BRAINLEIST OR WHATEVER JUSY HELP I NEED TO PASS