Move the decimal to right 3 times
Answer:
f(g(x)) = 2(x^2 + 2x)^2
f(g(x)) = 2x^4 + 8x^3 + 8x^2
Step-by-step explanation:
Given;
f(x) = 2x^2
g(x) = x^2 + 2x
To derive the expression for f(g(x)), we will substitute x in f(x) with g(x).
f(g(x)) = 2(g(x))^2
f(g(x)) = 2(x^2 + 2x)^2
Expanding the equation;
f(g(x)) = 2(x^2 + 2x)(x^2 + 2x)
f(g(x)) = 2(x^4 + 2x^3 + 2x^3 + 4x^2)
f(g(x)) = 2(x^4 + 4x^3 + 4x^2)
f(g(x)) = 2x^4 + 8x^3 + 8x^2
Hope this helps...
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The range is all the second values or ys
[-7, -1, 0, 2, 8]
Let one odd integer = x
other odd integer = x +2
Sum = x + x+2 = -44
=> 2x + 2 = -44
=> 2x = -44 -2 = -46
=> x = -46/2 = -23
x+2 = -23 + 2 = -21
Integers are -23 and -21
