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natima [27]
3 years ago
14

A stereo can be bought for $200 down and payments of $62.70 each month for 12 month. Find the total cost of the stereo

Mathematics
1 answer:
Ede4ka [16]3 years ago
4 0

Answer:

262.70

Step-by-step explanation:


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Write an expression for each quantity
Ira Lisetskai [31]
28) 7w
30) x/16
32) I/12
4 0
3 years ago
The measure of anglerst can be represented by the expression (6x 12)°. three lines extend from point s. the space between lines
miv72 [106K]

Answer:

  ∠RST = 120°

Step-by-step explanation:

We assume the positions of the lines and angles will match the attached figure. The angle addition theorem gives a relation that can be solved for x, then for the value of angle RST.

  ∠RSU +∠UST = ∠RST

__

  78° + (3x -12)° = (6x +12)° . . . . . substitute given values into the above

  54 = 3x . . . . . . . . . . . . . . . . divide by °, subtract 3x+12

  108 = 6x . . . . . . . . . . . multiply by 2

  120° = (6x +12)° = ∠RST . . . . add 12, show units

The measure of angle RST is 120 degrees.

_____

<em>Additional comment</em>

Note that we don't actually need to know the value of x (18) in this problem. We only need to know the value of 6x.

7 0
2 years ago
What number must you add to the expression below to complete the square? x^2-20x?
polet [3.4K]
We have that
x²<span>-20x
</span><span>Group terms that contain the same variable
</span>(x²-20x)
Complete the square 
(x²-20x+10²)------> (x-10)²

the answer is
the number must be 100
5 0
3 years ago
From a large number of actuarial exam scores, a random sample of scores is selected, and it is found that of these are passing s
Mnenie [13.5K]

<u>Supposing 60 out of 100 scores are passing scores</u>, the 95% confidence interval for the proportion of all scores that are passing is (0.5, 0.7).

  • The lower limit is 0.5.
  • The upper limit is 0.7.

In a sample with a number n of people surveyed with a probability of a success of \pi, and a confidence level of \alpha, we have the following confidence interval of proportions.

\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}

In which

z is the z-score that has a p-value of \frac{1+\alpha}{2}.

60 out of 100 scores are passing scores, hence n = 100, \pi = \frac{60}{100} = 0.6

95% confidence level

So \alpha = 0.95, z is the value of Z that has a p-value of \frac{1+0.95}{2} = 0.975, so z = 1.96.

The lower limit of this interval is:

\pi - z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.6 - 1.96\sqrt{\frac{0.6(0.4)}{100}} = 0.5

The upper limit of this interval is:

\pi + z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.6 + 1.96\sqrt{\frac{0.6(0.4)}{100}} = 0.7

The 95% confidence interval for the proportion of all scores that are passing is (0.5, 0.7).

  • The lower limit is 0.5.
  • The upper limit is 0.7.

A similar problem is given at brainly.com/question/16807970

5 0
3 years ago
Pls helppppppppppp nowwww
nika2105 [10]

Answer:

D is the answer. The graph was reflected across the y-axis, and shifted 1 unit downwards.

Step-by-step explanation:

Count the number of spaces to D, then to D'. They are the same (besides one being negative). A'B'C'D' was then shifted down 1 unit, which is why it is lower than shape ABCD.

3 0
3 years ago
Read 2 more answers
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