Answer:
F = 352 N
Explanation:
we know that:
F*t = ΔP
so:
F*t = M-M
where F is the force excerted by the wall, t is the time, M the mass of the ball, the final velocity of the ball and the initial velocity.
Replacing values, we get:
F(0.05s) = (0.8 kg)(11m/s)-(0.8 kg)(-11m/s)
solving for F:
F = 352 N
Answer:
Explanation:
The linear momentum during this collision must be conserved, which means that momentum before and after the collision must be the same.
We have a big defensive lineman of mass and velocity going in what we will call the positive direction, and a wide receiver of mass and velocity which we don't know. Since the collision is head on, momentum before the collision will be
After the collision, the receiver drops the lineman in his tracks, which means they come to a stop, so the momentum is null, and since this momentum must be equal to the one before the collision we have:
Which means:
So for we have:
where the negative sign indicates its opposite to our positive direction (of the big defensive lineman).
Answer:
Option c
Explanation:
Magnetic field lines form loops starting from north pole to south pole outside the magnet and from south pole to north pole inside the magnet.
Thus the field is such that it is directed outwards from the North pole and directed inwards to the South pole of the magnet.
A compass in a magnetic field will will comply with the magnet's North pole directing towards the magnetic field.
Answer: (a)
Explanation:
Given
Mass of large truck is 4M with velocity V
Mass of small car is M which is at rest
After the collision car and truck stick together
Conserving momentum
For elastic collision, the velocity of the center of mass remains the same as the momentum is conserved and there is no acceleration involved.
So, for elastic collision velocity
Answer:
0.4 m/s²
Explanation:
Given:
v₀ = 0.5 m/s
v = 2.5 m/s
t = 5 s
Find: a
v = at + v₀
2.5 m/s = a (5 s) + 0.5 m/s
a = 0.4 m/s²