Use the formula. Plug in known values, so you get f = 3000*2 and get 6000N as a result.
Answer:
0.23348 A
Explanation:
B = Magnetic field
v = Velocity of electron = ![1.38\times 10^7\ m/s](https://tex.z-dn.net/?f=1.38%5Ctimes%2010%5E7%5C%20m%2Fs)
q = Charge of electron = ![1.6\times 10^{-19}\ C](https://tex.z-dn.net/?f=1.6%5Ctimes%2010%5E%7B-19%7D%5C%20C)
= Vacuum permeability = ![4\pi \times 10^{-7}\ H/m](https://tex.z-dn.net/?f=4%5Cpi%20%5Ctimes%2010%5E%7B-7%7D%5C%20H%2Fm)
r = Radius of circle = 0.026 m
N = Number of turns = 103 turns/cm = ![103\times 100\ turns/m](https://tex.z-dn.net/?f=103%5Ctimes%20100%5C%20turns%2Fm)
I = Current
The magnetic and centripetal force will be balanced
![Bqv=m\frac{v^2}{r}\\\Rightarrow B=\frac{mv}{qr}](https://tex.z-dn.net/?f=Bqv%3Dm%5Cfrac%7Bv%5E2%7D%7Br%7D%5C%5C%5CRightarrow%20B%3D%5Cfrac%7Bmv%7D%7Bqr%7D)
The magnetic field in solenoid is given by
![B=N\mu_0 I\\\Rightarrow I=\frac{B}{N\mu_0}](https://tex.z-dn.net/?f=B%3DN%5Cmu_0%20I%5C%5C%5CRightarrow%20I%3D%5Cfrac%7BB%7D%7BN%5Cmu_0%7D)
From the first equation
![I=\frac{\frac{mv}{qr}}{N\mu_0}\\\Rightarrow I=\frac{mv}{N\mu_0qr}\\\Rightarrow I=\frac{9.11\times 10^{-31}\times 1.38\times 10^7}{103\times 100\times 4\pi \times 10^{-7}\times 1.6\times 10^{-19}\times 0.026}\\\Rightarrow I=0.23348\ A](https://tex.z-dn.net/?f=I%3D%5Cfrac%7B%5Cfrac%7Bmv%7D%7Bqr%7D%7D%7BN%5Cmu_0%7D%5C%5C%5CRightarrow%20I%3D%5Cfrac%7Bmv%7D%7BN%5Cmu_0qr%7D%5C%5C%5CRightarrow%20I%3D%5Cfrac%7B9.11%5Ctimes%2010%5E%7B-31%7D%5Ctimes%201.38%5Ctimes%2010%5E7%7D%7B103%5Ctimes%20100%5Ctimes%204%5Cpi%20%5Ctimes%2010%5E%7B-7%7D%5Ctimes%201.6%5Ctimes%2010%5E%7B-19%7D%5Ctimes%200.026%7D%5C%5C%5CRightarrow%20I%3D0.23348%5C%20A)
The current in the solenoid is 0.23348 A
Answer:
![v = 10.8 m/s^{2}](https://tex.z-dn.net/?f=v%20%3D%2010.8%20m%2Fs%5E%7B2%7D)
Explanation:
The centripetal force experienced by the steel toolbox is provided by the friction between the toolbox and the bed of the truck.
Therefore,
--------------------------------(1)
Here,
v - speed of truck
m - mass of toolbox
r - radius of curve around which the truck is turning
f - frictional force
μmg
In order to obtain Vmax, frictional force must also be max
Thus,
f = μmg--------------------------------------------------(2)
Substitute (2) in (1)
μmg
μgr
g - 9.8 m/![s^{2}](https://tex.z-dn.net/?f=s%5E%7B2%7D)
The standard value of coefficient of static friction between steel and steel is
μ ≈ 0.7
Therefore,
![v = 10.8 m/s^{2}](https://tex.z-dn.net/?f=v%20%3D%2010.8%20m%2Fs%5E%7B2%7D)
Answer:
Sub stratul exterior lichid-metal al miezului Pământului se află o bilă solidă de fier și aliaj de nichel cu aproximativ 1,60 km în diametru.
Explanation: