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Naddika [18.5K]
3 years ago
9

A girl throws a ball of mass 0.8 kg against a wall. The ball strikes the wall horizontally with a speed of 11 m/s, and it bounce

s back with this same speed. The ball is in contact with the wall 0.05 s. What is the average force exerted on the wall by the ball?
Physics
1 answer:
Karolina [17]3 years ago
3 0

Answer:

F = 352 N

Explanation:

we know that:

F*t = ΔP

so:

F*t = MV_f-MV_i

where F is the force excerted by the wall, t is the time, M the mass of the ball, V_f the final velocity of the ball and V_i the initial velocity.

Replacing values, we get:

F(0.05s) = (0.8 kg)(11m/s)-(0.8 kg)(-11m/s)

solving for F:

F = 352 N

 

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Answer:

Explanation:

Given

mass of children m_1=20\ kg

m_2=30\ kg

distance between two children L=3\ m

suppose  small child is at a distance of x m from  pivot point

so torque of small child and heavier child must be equal

20\times (x)=30\times (3-x)

2x=9-3x

5x=9

x=1.8\ m    

7 0
3 years ago
When a honeybee flies through the air, it develops a charge of +20 pC . Part A How many electrons did it lose in the process of
Yuri [45]

Answer:

1.3 × 10⁸ e⁻

Explanation:

When a honeybee flies through the air, it develops a charge of +20 pC = + 20 × 10⁻¹² C. This is a consequence of losing electrons (negative charges). The charge of 1 mole of electrons is 96468 C (Faraday's constant). The moles of electrons representing 20 pC are:

20 × 10⁻¹² C × (1 mol e⁻/ 96468 C) = 2.1 × 10⁻¹⁶ mol e⁻

1 mole of electrons has 6.02 × 10²³ electrons (Avogadro's number). The electrons is 2.1 × 10⁻¹⁶ moles of electrons are:

2.1 × 10⁻¹⁶ mol e⁻ × (6.02 × 10²³ e⁻/ 1 mol e⁻) = 1.3 × 10⁸ e⁻

7 0
4 years ago
what is cut off from the open sea coral reefs or sandbars A watershed B lagoon C reef or D atoll . also this is a science questi
Klio2033 [76]
Hello there.

Its D.

HOPE I HELPED

7 0
3 years ago
Read 2 more answers
A silver wire has a cross sectional area a = 2.0 mm2. a total of 9.4 × 1018 electrons pass through the wire in 3.0 s. the conduc
marta [7]
This problem uses the relationships among current I, current density J, and drift speed vd. We are given the total of electrons that pass through the wire in t = 3s and the area A, so we use the following equation to to find vd, from J and the known electron density n, so: 

v_{d} =  \frac{J}{n\left | q \right |}

<span>The current I is any motion of charge from one region to another, so this is given by:

</span>I = \frac{\Delta Q}{\Delta t} = \frac{9.4x1018electrons}{3s} = 3189.73(A)

The magnitude of the current density is:

J = \frac{I}{A} = \frac{3189.73}{2x10^{-6}} = 1594.86(A/m^{2})

Being:

A=2mm^{2} = 2x10^{-6}m^{2}
<span>
Finally, for the drift velocity magnitude vd, we find:

</span>v_{d} = \frac{1594.86}{5.8x1028\left |1.60x10^{-19}|\right } = 1.67x10^{18}(m/s)

Notice: The current I is very high for this wire. The given values of the variables are a little bit odd
6 0
3 years ago
How many protons are in Calcium? (* Hint: The Atomic number of Calcium is 20).
ryzh [129]

Answer:

The answer to your question is: 20

Explanation:

Atomic number is the number of proton and atom has. Each element has a specific number of protons, if the number of protons change, then this is a new element.

Mass number is the number of protons and neutrons and atom has.

                       Mass number = protons + neutrons

Data

Number of protons = ?

Atomic number = 20

Then,

           atomic number = number of protons = 20

3 0
3 years ago
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