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Alik [6]
3 years ago
12

What is the difference between current and voltage besides their units of measurement

Physics
1 answer:
kondor19780726 [428]3 years ago
8 0
"Voltage" is the "pressure" that makes electrons want to leave where they are
and head in some direction, if there's conducting material in that direction.

"Current" is the rate at which they all migrate in that direction.
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PLEASE HELPPP Count the number of atoms of each element in this molecule: 2H2K(OH2)2​
yulyashka [42]

Answer:

H = 6 atoms

K= 2 atoms

O = 2 atoms

7 0
3 years ago
Read 2 more answers
What is the new acceleration (in m/s/s)?
Delicious77 [7]

The new acceleration is 108 m/s^2

Explanation:

We can answer this problem by applying Newton's second law, which states that:

F=ma

where

F is the net force on an object

m is the mass of the object

a is its acceleration

The equation can be rewritten as

a=\frac{F}{m}

In this problem, the initial acceleration is

a=18.0 m/s^2

Later:

- The net force is tripled: F'=3F

- The mass is halved: m'=\frac{m}{2}

Therefore, the new acceleration is:

a'=\frac{F'}{m'}=\frac{3F}{m/2}=6\frac{F}{m}=6a

which means that the new acceleration is 6 times the original acceleration, therefore

a'=6(18)=108 m/s^2

Learn more about acceleration:

brainly.com/question/9527152

brainly.com/question/11181826

brainly.com/question/2506873

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#LearnwithBrainly

8 0
3 years ago
A stretched string has a mass per unit length of 5.40 g/cm and a tension of 17.5 N. A sinusoidal wave on this string has an ampl
kondaur [170]

Answer:

Part a)

y_m = 0.157 mm

part b)

k = 101.8 rad/m

Part c)

\omega = 579.3 rad/s

Part d)

here since wave is moving in negative direction so the sign of \omega must be positive

Explanation:

As we know that the speed of wave in string is given by

v = \sqrt{\frac{T}{m/L}}

so we have

T = 17.5 N

m/L = 5.4 g/cm = 0.54 kg/m

now we have

v = \sqrt{\frac{17.5}{0.54}}

v = 5.69 m/s

now we have

Part a)

y_m = amplitude of wave

y_m = 0.157 mm

part b)

k = \frac{\omega}{v}

here we know that

\omega = 2\pi f

\omega = 2\pi(92.2) = 579.3 rad/s

so we  have

k = \frac{579.3}{5.69}

k = 101.8 rad/m

Part c)

\omega = 579.3 rad/s

Part d)

here since wave is moving in negative direction so the sign of \omega must be positive

4 0
3 years ago
Can you guys please help with this question?
Alexandra [31]

they act as sunshades from the sun intensity, and filters

3 0
3 years ago
A shopper pushes a 5.32 kg grocery cart with a 12.7 N force directed at -28.7° below horizontal. A friction force of 8.33 N push
atroni [7]

Answer:

0.8214 m/s^2

Explanation:

Fnet= Fpushed - Ffriction

Fpushed = 12.7N      Ffriction = 8.33N

Fnet = 12.7N - 8.33N = 4.37N

Fnet= mass(acceleration)

Fnet = 4.37N    mass = 5.32 kg

4.37N = 5.32 kg(acceleration)

acceleration= 0.8214 m/s^2

3 0
3 years ago
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