Answer:
a) t = 0.528 s
b) D = 1.62 m
Explanation:
given,
speed of the baseball = 3.75 m/s
angle made with the horizontal = 35°
height of the roof edge = 2.5 m
using equation of motion
![s = ut +\dfrac{1}{2}gt^2](https://tex.z-dn.net/?f=s%20%3D%20ut%20%2B%5Cdfrac%7B1%7D%7B2%7Dgt%5E2)
![2.5 = vsin\theta \ t +\dfrac{1}{2}gt^2](https://tex.z-dn.net/?f=2.5%20%3D%20vsin%5Ctheta%20%5C%20t%20%2B%5Cdfrac%7B1%7D%7B2%7Dgt%5E2)
![2.5 = 3.75\ sin35^0 \ t +\dfrac{1}{2}\times 9.8 t^2](https://tex.z-dn.net/?f=2.5%20%3D%203.75%5C%20sin35%5E0%20%5C%20t%20%2B%5Cdfrac%7B1%7D%7B2%7D%5Ctimes%209.8%20t%5E2)
4.9 t² + 2.15 t - 2.5 = 0
on solving the above equation
t = 0.528 s
b) D = v cos θ × t
D = 3.75 × cos 35° ×0.528
D = 1.62 m
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