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Dafna11 [192]
2 years ago
8

A druggist needs 25 liters of a solution that is 16% iodine. She has one solution that is 12 % iodine and another that is 37 %.

How many liters of each should a druggist mix together
Mathematics
1 answer:
GalinKa [24]2 years ago
7 0

Answer:

21 liters of the 12% solution and 4 liters of the 37% solution

Step-by-step explanation:

Represent the number of liters of the first solution as x and the second as y. Now, the total liters of iodine is going to be 16% of 25 = 4 liters of iodine, and the total liters of each solution is going to be 25. Now, we can setup two equations:

0.12x+0.37y = 4

x + y = 25

Multiplying the bottom equation by 0.12, we have

0.12x + 0.12y = 3

Subtracting, we have

0.12x+0.37y=4

-

0.12x + 0.12y = 3

= 0.25y = 1

= y = 4

= x = 25 - 4 = 21

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Answer:

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Step-by-step explanation:

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7 0
3 years ago
How do you solve this??
DochEvi [55]

Answer:

Step-by-step explanation:

Hi Millie.

First we can realize that the number of cubes of each type does not matter, only the ratios between them. We see that if there are x yellow cubes, there are 3x blue cubes. And therefore, there are 5*3x green cubes, or 15x green cubes. This means that the cubes are in a 1:3:15 ratio, or that for every 1 yellow cube, there are 3 blue and 15 green cubes.

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patriot [66]
Measure of Hypotaneous = 5√5

And it's already given that b = 2a

By using pythagoras theorem:

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Let's substitute for b as 2a in above equation we'll get:

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3 0
3 years ago
Read 2 more answers
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