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Dafna11 [192]
2 years ago
8

A druggist needs 25 liters of a solution that is 16% iodine. She has one solution that is 12 % iodine and another that is 37 %.

How many liters of each should a druggist mix together
Mathematics
1 answer:
GalinKa [24]2 years ago
7 0

Answer:

21 liters of the 12% solution and 4 liters of the 37% solution

Step-by-step explanation:

Represent the number of liters of the first solution as x and the second as y. Now, the total liters of iodine is going to be 16% of 25 = 4 liters of iodine, and the total liters of each solution is going to be 25. Now, we can setup two equations:

0.12x+0.37y = 4

x + y = 25

Multiplying the bottom equation by 0.12, we have

0.12x + 0.12y = 3

Subtracting, we have

0.12x+0.37y=4

-

0.12x + 0.12y = 3

= 0.25y = 1

= y = 4

= x = 25 - 4 = 21

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Answer:

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Step-by-step explanation:

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Given principal is $16,000, i=3% and n=10, m=4:

(1+i_m)=(1+i/m)^m\\\\=(1+0.03/4)^4=1.03034\\\\\therefore A=16000(1.03034)^{10}\\\\=21573.75

#For account B:

Given principal is $16,000, i=3% and n=10, m=12:

(1+i_m)=(1+i/m)^m\\\\=(1+0.03/12)^{12}=1.03042\\\\\therefore A=16000(1.03042)^{10}\\\\\\\\=21589.66

We compare the amounts after 10 years and get the difference:

B>A\\\\B-A=21589.66-21573\\\\=\$15.91

Hence, account B has the most value after 10 years and has a value of $21,589.66

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Citrus2011 [14]

Answer:

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