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Leno4ka [110]
3 years ago
9

A certain reaction has an activation energy of 67.0 kJ/mol and a frequency factor of A1 = 4.20×1012. What is the rate constant,

k, of this reaction at 24.0 degrees C?
Chemistry
1 answer:
MrRa [10]3 years ago
5 0

Answer:

  • K = 7.00

Explanation:

<u>1) Arrhenius equation</u>

Arrhenius equation shows the relation between activation energy, temperature, and the equilibrium constant.

This is the equation:

       K=Ae^{-Ea/RT}

Where:

  • K is the equilibrium constant,
  • A is the frequency factor,
  • Ea is the activation energy (in J/mol),
  • T is the temperature in kelvins (K), and
  • R is the universal constant.

<u></u>

<u>2) Substitute, using the right units, and compute:</u>

  • A = 4.20 × 10¹² (dimensionless)
  • Ea = 67.0 kJ/mol = 67,000 J/mol
  • T = 24.0°C = 24.0 + 273.15 K = 297.15 K
  • R = 8.314 J/K mol

K=Ae^{-Ea/RT}=(4.20)(10)^{12}e^{-67,000J/mol/(8.314J/molK.297.15K)}

  • K = 7.00
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4. To how much water should 50 mL of 12 M hydrochloric acid be added to
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Explanation :

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M_1\text{ and }V_1 are the initial molarity and volume of HCl.

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We are given:

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Fractional distillation is used to separated
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When sodium phosphate reacts with sulfuric acid, forming sodium sulfate and phosphoric acid, the stoichiometric coefficient for sulfuric acid in the balanced chemical equation is 3.

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The chemical equation for the given reaction is:

Na_{3} PO_{4} + H_{2} SO_{4} = Na_{2} SO_{4} + H_{3} PO_{4}

Put the necessary stoichiometric coefficient to balance each element.

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Balancing P:

2Na_{3} PO_{4} + H_{2} SO_{4} = 3Na_{2} SO_{4} + 2H_{3} PO_{4}

Balancing S:

2Na_{3} PO_{4} + 3H_{2} SO_{4} = 3Na_{2} SO_{4} + 2H_{3} PO_{4}

Notice that H and O are already balanced.

Hence, the balanced chemical equation for the reaction is:

2Na_{3} PO_{4} + 3H_{2} SO_{4} = 3Na_{2} SO_{4} + 2H_{3} PO_{4}

where 3 is the stoichiometric coefficient of sulfuric acid, H_{2} SO_{4}.

Learn more about stoichiometric coefficient here: brainly.com/question/6666875

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