Answer:
The volume of feedstock needed to mantain an organic load rate of 2 kgVS/day is 0.055 m3/day of feedstock.
The HRT is 20.6 days.
Explanation:
First, we calculate how many kg is 1 m3 of feedstock. We know the density, so we can calculate the mass:

If the VS are 6% in weight,

The volume per day needed to feed 2 kg of VS/day is:

The HRT depends on the volume of the tank and the flow. Its equation is

1) cobalt u can tell bc on a periodic table there is a small number that on cobalt is 27.
2) think that would be 11 bc in the 4th shell there can be up to 18 electrons
Explanation:
Since the ratio is Cu/Fe, if some Fe were lost due to spillage, the Cu/Fe ratio would INCREASE because Fe would be lower.
equalize the coefficients:
Al(NO3)3+3NaCl=3NaNO3+AlCl3
according to the equation 1 mol Al(NO3)3 reacted with 3 moles NaCl. hence, 4 moles Al(NO3)3 should react with 12 moles NaCl, and 9 moles reacted NaCl. So NaCl is limiting, we decide further on this reagent.
\frac{9}{3}=\frac{x}{3}
3
9
=
3
x
x=9
9 moles NaNO3