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devlian [24]
3 years ago
7

HELP PLEASE !!!! DUE NOW!!

Chemistry
1 answer:
ratelena [41]3 years ago
6 0

Answer:

The ratio of the products to reactants remains caonstant over time

Explanation:

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The work function of a silver surface is 4.73 eV. What would happen if the silver is hit with a photon with 2.5 eV of energy?
DerKrebs [107]

Answer:Nothing, the photon just bounces off the surface.

Explanation:

According to Albert Einstein, a photoelectron can only be emitted from a metal surface when the energy of the incident photon is greater than the work function of the metal.

In the scenario described in the question, the work function of the metal is greater than the energy of the photon. Hence, the photon just bounces off the metal surface without emitting any electron.

6 0
3 years ago
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You have 1169.6 g of a bleach solution. The percent by mass of the solute sodium hypochlorite, NaOCl, is 3.62%. How many grams o
Aneli [31]

Answer:

Mass of solvent is 1127.3 g

Explanation:

NaOCl → 3.62%

This percent means, that in 100 g of bleach solution, there are 3.62 g of NaOCl. So let's make a rule of three:

100 g of bleach solution have 3.62 g

1169.6 g of bleach solution may have (1169.6  . 3.62) /100 = 42.3 g

42.3 g is the mass of NaOCl in the solution

Mass of solution = Mass of solvent + Mass of solute

1169.6 g = Mass of solvent + 42.3 g

1169.6 g - 42.3 g = Mass of solvent → 1127.3 g

7 0
3 years ago
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What is the best reason for the scientific community to accept a theory?
Marianna [84]

Answer: The best reason the scientific community will accept a theory is if it is proven.

4 0
3 years ago
What is the Molarity of a solution of HNO3 if it contains 12.6 moles in a<br> 0.75 L solution? *
Korolek [52]

Answer:

M = 16.8 M

Explanation:

<u>Data:</u> HNO3

moles = 12.6 moles

solution volume = 0.75 L

Molarity is represented by the letter M and is defined as the amount of solute expressed in moles per liter of solution.

M=\frac{moles}{solution volume}

The data is replaced in the given equation:

M=\frac{12.6 mol}{0.75L}=16.8\frac{mol}{L}

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3 years ago
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The product formation was decreased when a substance b was added to an enzyme reaction. more substrate being added did not incre
borishaifa [10]
When the product formation is decreased if a substance B is added to an enzyme reaction and more substrate being added would not increase the amount of produce formed, then we assume that substance b could be a noncompetitive inhibitor. This type of inhibitor would be one that would bind to the enzyme with or without the presence of a substrate in different sites at the same time. It would change the conformation of the enzyme and also the active sites. As a result, the substrate would not be able to bind to the enzyme more effectively than the usual. The overall efficiency would decrease.
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