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3 years ago

Which example illustrates the idea of "collecting data"?

Computers and Technology

2 answers:

Gre4nikov [31]3 years ago

8 0

A mining all product reviews from an online store for further processing

ivolga24 [154]3 years ago

5 0

Answer:

A. mining all product reviews from an online store for further processing.

Explanation:

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Oxnard Casualty wants to ensure that their e-mail server has 99.98 percent reliability. They will use several independent server

sattari [20]

Answer:

The smallest number of servers required is 3 servers

Explanation:

Given

$Reliability = 99.98\%$

$Individual Servers = 95\%$

Required

Minimum number of servers needed

Let p represent the probability that a server is reliable and the probability that it wont be reliable be represented with q

Such that

$p = 95\%\\$

It should be noted that probabilities always add up to 1;

So,

$p + q = 1$ '

Subtract p from both sides

$p - p + q = 1 - p$

$q = 1 - p$

Substitute $p = 95\%\\$

$q = 1 - 95\%$

Convert % to fraction

$q = 1 - \frac{95}{100}$

Convert fraction to decimal

$q = 1 - 0.95$

$q = 0.05$

------------------------------------------------------------------------------------------------

To get an expression for one server

The probabilities of 1 servers having 99.98% reliability is as follows;

$p = 99.98\%$

Recall that probabilities always add up to 1;

So,

$p + q = 1$

Subtract q from both sides

$p + q - q = 1 - q$

$p = 1 - q$

So,

$p = 1 - q = 99.98\%$

$1 - q = 99.98\%$

Let the number of servers be represented with n

The above expression becomes

$1 - q^n = 99.98\%$

Convert percent to fraction

$1 - q^n = \frac{9998}{10000}$

Convert fraction to decimal

$1 - q^n = 0.9998$

Add $q^n$ to both sides

$1 - q^n + q^n= 0.9998 + q^n$

$1 = 0.9998 + q^n$

Subtract 0.9998 from both sides

$1 - 0.9998 = 0.9998 - 0.9998 + q^n$

$1 - 0.9998 = q^n$

$0.0002 = q^n$

Recall that $q = 0.05$

So, the expression becomes

$0.0002 = 0.05^n$

Take Log of both sides

$Log(0.0002) = Log(0.05^n)$

From laws of logarithm $Loga^b = bLoga$

So,

$Log(0.0002) = Log(0.05^n)$ becomes

$Log(0.0002) = nLog(0.05)$

Divide both sides by $Log0.05$

$\frac{Log(0.0002)}{Log(0.05)} = \frac{nLog(0.05)}{Log(0.05)}$

$\frac{Log(0.0002)}{Log(0.05)} = n$

$n = \frac{Log(0.0002)}{Log(0.05)}$

$n = \frac{-3.69897000434}{-1.30102999566}$

$n = 2.84310893421$

$n = 3 (Approximated)$

Hence, the smallest number of servers required is 3 servers

6 0

3 years ago

An organization's IRP prioritizes containment over eradication. An incident has been discovered where an attacker outside of the

djyliett [7]

Answer:

a. Remove the affected servers from the network.

Explanation:

An organization's incident response process (IRP) can be defined as all of the process involved in the cleanup and recovery of data when they fall victim to an attack or cybersecurity breach. The incident response process comprises of six (6) important stages and these are;

1. Preparation.

2. Detection and analysis (identification).

3. Containment.

4. Eradication.

5. Recovery.

6. Review of incident activities.

When an organization's IRP prioritizes containment over eradication and an incident is discovered, where an attacker outside the organization installed a crypto-currency mining software on the organization's web servers. Given the organization's stated priorities, the cybersecurity engineer should remove the affected servers from the network.

A containment process is focused on taking steps to eliminate or contain the attack. It basically involves acting swiftly in response to the attack, so as to prevent it from spreading across board or in order to mitigate the damage already caused.

In this context, the cybersecurity engineer should remove the affected servers from the network in accordance with the organization's IRP priority (containment).

Furthermore, he could take a step further to contain the attack by installing a firewall and updating their policies in the Intrusion Prevention System (IPS) of the organization.

5 0

3 years ago

1. In which generation were semiconductor memories used for the first time:

Llana [10]

1: D. Third Generation

2: C. 10

4 0

3 years ago

Which pair of properties apply to both sound and electromagnetic waves?

Alex73 [517]

Both waves can have interference, reflection, and diffraction.

Wave interference is a phenomenon that occurs when two waves meet while traveling along the same medium. The interference of waves causes the medium to take on a shape that results from the net effect of the two individual waves upon the particles of the medium.

Wave reflection happens when a wave reaches the boundary between one medium and another medium, a portion of the wave undergoes reflection and a portion of the wave undergoes transmission across the boundary.

Wave diffraction involves a change in direction of waves as they pass through an opening or around a barrier in their path.

3 0

3 years ago

Read 2 more answers

Write a class called MagicSquare, which contains a single method called check that accepts a two-dimensional array as an argumen

ira [324]

Answer:

public class MagicSquare {

public static void main(String[] args) {

int[][] square = {

{ 8, 11, 14, 1},

{13, 2, 7,12},

{ 3, 16, 9, 6},

{10, 5, 4, 15}

};

System.out.printf("The square %s a magic square. %n",

(isMagicSquare(square) ? "is" : "is not"));

}

public static boolean isMagicSquare(int[][] square) {

if(square.length != square[0].length) {

return false;

}

int sum = 0;

for(int i = 0; i < square[0].length; ++i) {

sum += square[0][i];

}

int d1 = 0, d2 = 0;

for(int i = 0; i < square.length; ++i) {

int row_sum = 0;

int col_sum = 0;

for(int j = 0; j < square[0].length; ++j) {

if(i == j) {

d1 += square[i][j];

}

if(j == square.length-i-1) {

d2 += square[i][j];

}

row_sum += square[i][j];

col_sum += square[j][i];

}

if(row_sum != sum || col_sum != sum) {

return false;

}

return d1 == sum && d2 == sum;

}

5 0

3 years ago