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Basile [38]
2 years ago
14

Omg please i need help this is worth sm pointssss PLEASE BESTIES

Mathematics
1 answer:
dalvyx [7]2 years ago
7 0

Answer: 1. don't call me your bestie...

2. the answer is A. 72 B. 75 C. 55 D. 52 E. 112 F. 55 G. I'm not sure what G is

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Siena draws a map of her flower garden. She wants to plant roses 6 feet away from the marigolds and 5 feet away from the lavende
vfiekz [6]

Answer:

no pictur no answer

Step-by-step explanation:

8 0
3 years ago
PLEASE HELP
Sholpan [36]
1) We have that the equation is x^2=20y , hence y=x^2/20. The standard equation of such an equation is y=\frac{1}{4p} x^2. Hence, p=5 in this case. The focus is at (0,5) and the directrix is at y=-5 (a tip is that the directrix is always "opposite" the focus point of a parabola; if the directrix is at x=-7 for example, the focus is at (7,0)).
2) Similarly, we have that the equation is x=3y^2 \\  \frac{1}{4p} =3. Thus, p=1/12. In this case, the parabola opens along the x-axis and the focus is at (1/12, 0). Also, the directrix is at x=-1/12. Hence the correct answer is B.
3) We are given that the parabola has a p of 9. Also, the focus lies along the y-axis, hence the parabola is opening along the y-axis. Finally, the focus is on the positive half, so the parabola is opening upwards. The equation for this case is y=y=\frac{1}{4p} x^2= \frac{1}{36 } x^2.
4) Similarly as above. The directrix is superfluous, we only need the p-value. THe same comments about the parabola apply and if we substitute p=8 in the formula: y= \frac{1}{4p} x^2 we get y=\frac{1}{32} x^2.
5) This is somewhat different, even though we do not need the directrix again. The focus lies on the x-axis, thus the parabola opens in this direction. The focus lies on the positive part of the axis, thus the parabola opens to the right. We also are given p=7. Hence, the equation we need is of the formx= \frac{1}{4p} y^2. Substituting p=7, we get x= \frac{1}{28} y^2.
6) The equation of a prabola with a vertex at (0,0) is of the form y=-ax^2. The minus sign is needed since the parabola is downwards. Since we are given anothe point, we can calculate a. We have to take y=-74 and x=14 feet (since left to right is 28, we need to take half). -a= \frac{y}{x^2} = \frac{-74}{14^2} =-0.378. Thus a=0.378. Hence the correct expressions is y=-0.378*x^2
7 0
3 years ago
Read 2 more answers
Evaluate the following integrals: 1. Z x 4 ln x dx 2. Z arcsin y dy 3. Z e −θ cos(3θ) dθ 4. Z 1 0 x 3 √ 4 + x 2 dx 5. Z π/8 0 co
Zigmanuir [339]

Answer:

The integrals was calculated.

Step-by-step explanation:

We calculate integrals, and we get:

1) ∫ x^4 ln(x) dx=\frac{x^5 · ln(x)}{5} - \frac{x^5}{25}

2) ∫ arcsin(y) dy= y arcsin(y)+\sqrt{1-y²}

3) ∫ e^{-θ} cos(3θ) dθ = \frac{e^{-θ} ( 3sin(3θ)-cos(3θ) )}{10}

4) \int\limits^1_0 {x^3 · \sqrt{4+x^2} } \, dx = \frac{x²(x²+4)^{3/2}}{5} - \frac{8(x²+4)^{3/2}}{15} = \frac{64}{15} - \frac{5^{3/2}}{3}

5)  \int\limits^{π/8}_0 {cos^4 (2x) } \, dx =\frac{sin(8x} + 8sin(4x)+24x}{6}=

=\frac{3π+8}{64}

6)  ∫ sin^3 (x) dx = \frac{cos^3 (x)}{3} - cos x

7) ∫ sec^4 (x) tan^3 (x) dx = \frac{tan^6(x)}{6} + \frac{tan^4(x)}{4}

8)  ∫ tan^5 (x) sec(x)  dx = \frac{sec^5 (x)}{5} -\frac{2sec^3 (x)}{3}+ sec x

6 0
3 years ago
Answer 3(x-4)=2(-2x+1). Explain
Lelu [443]

Answer:

65

Step-by-step explanation:

6 0
3 years ago
ZC and ZD are vertical angles with mZC = -3x+58 and mZD= x - 2.
kogti [31]

Answer:

×=-2

0=×-2

×=-2

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3 0
3 years ago
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