In the question there are numerous information's of immense importance already given. Let us write them down first
Distance traveled by bike = x km
Distance traveled by bus = y km
Total distance traveled by George and Carmen = 325 km
Then
x + y = 325
Another equation can be determined by
x - y = 75
x = y + 75
Now we will put the value of x in relation to y in the first equation.
x + y =325
y + 75 + y = 325
2y = 325 - 75
2y =250
y = 250/2
= 125 km
Now putting the value of y in equation given below, we get
x + y = 325
x + 125 = 325
x = 325 - 125
= 200 km
So the distance they biked is 200 km and the distance they traveled by bus is 125 km.
Answer:
-4m-17
Step-by-step explanation:
g(2m+7) = -2*(2m+7) -3
= -4m -14 -3
= -4m -17
Answer:
<h2>
The right option is twelve-fifths</h2>
Step-by-step explanation:
Given a right angle triangle ABC as shown in the diagram. If ∠BCA = 90°, the hypotenuse AB = 26, AC = 10 and BC = 24.
Using the SOH, CAH, TOA trigonometry identity, SInce we are to find tanA, we will use TOA. According to TOA;
Tan (A) = opp/adj
Taken BC as opposite side since it is facing angle A directly and AC as the adjacent;
tan(A) = BC/AC
tan(A) = 24/10
tan(A) = 12/5
The right option is therefore twelve-fifths
Answer:
The distance between the two train stations is 1728 km
Step-by-step explanation:
The speed of the bus = 54 km/h
The speed of the truck = 48 km/h
When the bus and truck meet again, the distance covered by the bus = 216 km more than he distance traveled by the truck
Let the distance between the two train stations = x
Let the location where they first meet be y from station A we have;
The location where they meet again = y - 216 km
Therefore, we have;
Location where they
The time for the truck and the bus to meet again = t
Therefore, 54 × t - 48 × t = 216 km
6·t = 216 km
t = 36 hours
Therefore, the time for the bus to travel x + 216 km = 36 hours
54 × 36 = 1944 = x + 216
x = 1944 - 216 = 1728 km
The distance between the two train stations = 1728 km.
Answer:
a(n) = 1 + 7(n-1)
Step-by-step explanation:
