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2 years ago

812.16 is what percent of 752?

Mathematics

2 answers:

belka [17]2 years ago

8 0

Answer:

108

Step-by-step explanation:

For 100, our answer will be 108

For 752, our answer will be x

100*x = 108*752 (In Step 1 and 2 see colored text; Diagonal multiplications will always be equal)

x = 108*752/100 = 81216/100 = 812.16

Answer: 108 percent of 752 is 812.16

finlep [7]2 years ago

3 0

108 is the answer to your question

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2 years ago

Find a number in the sequence 1) 100, 400, 610, ?, 652 2) 342, 128, ?, 26

dsp73

Answer:

1. 460

2. 216

Step-by-step explanation:

From the series ,

100 , 400 , 610 , ? , 652

Writing the the digits in the revere order , i.e

001 , 004 , 016 , ? , 256

Now,

Now , getting the number in the form of the multiple of 4 as -

1 , 1 * 4 = 4 , 4 * 4 = 16 , ? , 64 * 4 = 4

Hence , the value for ? = 16 * 4 = 64 .

Again , reversing 64 to get the missing number of the series -

460 .

Hence ,

The value for ? is 460 .

From the series ,

342 , 128 , ? , 26

Now, multiplying the first digit with the second digit and merging it to the product of the second and third digit -

3 * 4 and 4 * 2 , 1 * 2 and 2 * 8 , ?

128 , 216 , ?

Hence ,

The value for question mark = 1 * 2 and 1 * 6 = 216

Hence ,

The value for ? is 216 .

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3 years ago

What is the length of one leg of the triangle? 11 units 11/units 22 units 22/2 units

son4ous [18]

Answer:

The length of one leg of the triangle is 22 units

Step-by-step explanation:

The complete question in the attached figure

Let

x ----> the length of one leg of the triangle

we know that

In the right isosceles triangle of the figure

The cosine of angle of 45 degrees is equal to the adjacent side to angle of 45 degrees divided by the hypotenuse

$cos(45\°)=\frac{x}{22\sqrt{2}}$ ---> equation A

$cos(45\°)=\frac{\sqrt{2}}{2}$ ----> equation B

equate equation A and equation B and solve for x

$\frac{x}{22\sqrt{2}}=\frac{\sqrt{2}}{2}$

$x=\frac{\sqrt{2}}{2}(22\sqrt{2})=22\ units$

therefore

The length of one leg of the triangle is 22 units

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3 years ago

What is the probability that a point chosen at random in the given figure will be inside the larger triangle and outside the sma

Anna007 [38]

Given:
Area of a triangle = (h*b) / 2

Area of smaller triangle = (4cm * 4cm) / 2 = 16cm² / 2 = 8 cm²
Area of larger triangle = (6cm * 10cm) / 2 = 60cm² / 2 = 30 cm²

30cm² - 8cm² = 22cm²

Probability that the point is inside the large triangle but outside the small triangle:

22cm² / 30cm² → 11/15 → 0.73 or 73%

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