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LiRa [457]
2 years ago
7

2^x+2=4. yall i got this problem and i dont rlly understand how to do it. Hope yall can help me:)))))))))))))))

Mathematics
2 answers:
elena-s [515]2 years ago
6 0

Answer:

x=1

Step-by-step explanation:

2^x=4-2

2^x=2

2^x=2^1

x=1

Oksi-84 [34.3K]2 years ago
3 0

Answer:

x=1

Step-by-step explanation:

Ok, so we start off with 2^x+2=4

Then, we subtract 2 from both sides so that becomes: 2^x+2-2=4-2

After that, we simplify to get: 2^x=2

Finally, the solution becomes: x=1

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What percent of 55 is 21.1
Rama09 [41]

11.6, if you need a decimal. it's in between 11 and 12

5 0
3 years ago
What is 3x^2-2n-5=0<br> please help me!!!
expeople1 [14]
The answer to your question is: 
It is a quadratic equation in 'x', with 'n' mistakenly typed in the second term..

Although you didn't ask for the solutions to the equation, I'm already here
so I might as well go through it and find them:

<span><u>3x² - 2x - 5 = 0</u></span>

In terms of the generic quadratic formula:
A = 3
B = -2
C = -5

Plug those into the quadratic formula, and you discover that

<u>x = -1</u>
and
<u>x = ⁵/₃</u>
7 0
3 years ago
Read 2 more answers
What are the solutions of the quadratic function 49x2=9
mylen [45]

Answer:

49x^2 - 9 = 0As there is no x term, we can pretty much guess we have a situation where we factlrise by something known aa difference of two squares, so to factorise it:49 = 7^29 = 3^2x^2 = (x)^2so...(7x - 3)(7x + 3) = 07x - 3 = 0 7x + 3 = 0x = 3/7 x = -3/7

Step-by-step explanation:

3 0
3 years ago
Read 2 more answers
PLEASE HELP!!! A group has at most $140 to spend on an event space. The inequality 15h + 40 140 represents the cost to rent the
Zielflug [23.3K]

9514 1404 393

Answer:

  h ≤ 6 2/3

Step-by-step explanation:

The inequality is presumed to be ...

  15h +40 ≤ 140

  15h ≤ 100

  h ≤ 6 2/3

__

The graph shows h ≥ 0, because the inequality is only reasonable for h ≥ 0.

3 0
2 years ago
What is the solution to the system of equations?<br><br> 6x – 9y = 16<br><br> 2x – 3y = 7
kifflom [539]
The first step for solving this problem is to multiply both sides of the bottom equation by -3.
\left \{ {{6x-9y=16} \atop {-6x + 9y = -21}} \right.
Add the two equations together.
6x - 9y - 6x + 9y = 16 - 21
Eliminate the opposites.
-9y + 9y = 16 - 21
Remember that the sum of two opposites equals 0,, so the equation becomes the following:
0 = 16 - 21
Calculate the difference on the right side of the equation.
0 = -5
This means that the statement \left \{ {{6x-9y=16} \atop {2x-3y=7}} \right. is false for any value of x and y. That means that the answer to your question is (x,y) ∈ ∅,, or no solution.
Let me know if you have any further questions.
:)
8 0
3 years ago
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