Conversion process of non-organic carbon dioxide into organic compounds by living organisms.
Example: Photosynthesis
Answer:
(a) Pair 1: H₂S and HS⁻
Pair 2: NH₃ and NH₄⁺
(b) Pair 1: HSO₄⁻ and SO₄⁻
Pair 2: NH₃ and NH₄⁺
(c) Pair 1: HBr and Br⁻
Pair 2: CH₃O⁻ and CH₃OH
(d) Pair 1: HNO₃ and NO₃⁻
Pair 2: H₃O⁺
Explanation:
When an acid loses its proton (H⁺), a conjugate base is produced.
When a base accepts a proton (H⁺), it forms a conjugate acid.
(a) H₂S is an acid. When it loses a proton, it forms the conjugate base HS⁻.
NH₃ is a base. When NH₃ gains a proton, it forms the conjugate acid NH₄⁺
(b) The acid HSO₄⁻ loses a H⁺ ion and forms the conjugate base SO₄²⁻.
The base NH₃ accepts a H⁺ ion to form the conjugate acid NH₄⁺.
(c) HBr is an acid. When loses the H⁺ ion, it forms the conjugate base Br⁻.
CH₃O⁻ accepts a H⁺ ion to form the conjugate acid CH₃OH.
(d) HNO₃ loses a proton to form the conjugate base NO₃⁻.
H₂O gains a proton to form the conjugate acid H₃O⁺.
Answer:
an alloy is a mixture of elements that has metallic properties
Explanation:
Answer:
The coefficient is 1
Explanation:
CaO(s) + CO2(g) -> CaCO3(s)
In the balanced equation, the coefficient for CaO is 1
The coefficient represents the number of moles of a compound in the stoichiometry of the reaction
Answer:
Average atomic mass = 58.51047 amu
The symbol is 
Explanation:
The formula for the calculation of the average atomic mass is:
Given that:
For first isotope:
% = 68.274 %
Mass = 57.9353 amu
For second isotope:
% = 26.095 %
Mass = 58.9332 amu
For third isotope:
% = 1.134 %
Mass = 61.9283 amu
For fourth isotope:
% = 3.593 %
Mass = 63.9280 amu
For fifth isotope:
% = 0.904 %
Mass = 63.9280 amu
Thus,
Average atomic mass = 58.51047 amu
The symbol is
