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Ksju [112]
3 years ago
14

The empirical formula of styrene is CH; its molar mass is 104.1 g/mol. What is the molecular formula of styrene?

Chemistry
2 answers:
Natalija [7]3 years ago
7 0
You got the answer correct. If you would double check
given:C (12 g/mol) H (1 g/mol). 

12(8) + 1(8) = 104 g/mol

and for C2H4
12(2)+1(4) = 28g/mol

Also, chemical formula of styrene is<span> C6H5CH=CH2.</span>
arlik [135]3 years ago
5 0
1. Find the molecular formula of styrene 

<span>Molecular formula = n x empirical formula </span>

<span>n= 104.14/13.02 = 8 where 13.02 is the empirical mass of CH </span>

<span>Molecular formula = CH x 8 </span>
<span>= C8H8 </span>

<span>2. From step 1, one molecule of styrene contains 8 atoms of hydrogen or one mole of styrene molecules contains 8 moles of hydrogen atoms (remember the formula of styrene is C8H8). </span>

<span>3. Convert 3.49 g styrene to mole styrene </span>

<span>mole styrene = 3.49 g/104.14 g/mol = 4.71 x 10^-3 mole </span>

<span>4. Calculate mole of hydrogens equivalent to 4.71 x 10^-3 mole styrene. Use mole ratio from step 2. </span>

<span>mole H = 4.71 x 10^-3 mole styrene * 8 moles H/1 mole styrene </span>

<span>mole H = 0.0377 mole </span>

<span>5. Find number of H atoms contained in 0.0377 mole of hydrogen atoms. Use Avogadro's number. </span>

<span>no. of H atoms = 0.0377 mole H * 6.02 x 10^23 atoms H/1mole H </span>

<span>no. of H atoms = 2.27 x 10^22 atoms H</span>
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Answer:

12 L of 40% sulfuric acid solution and 8 L of 10% sulfuric acid solution are needed to make 20 L of sulfuric acid solution.

Explanation:

For first solution of sulfuric acid :

C₁ = 40% , V₁ = ?

For second solution of sulfuric acid :

C₂ = 10% , V₂ = ?

For the resultant solution of sulfuric acid:

C₃ = 28% , V₃ = 20L

Also,

<u>V₁ + V₂ = V₃ = 20L</u> ......................................(1)

Using

<u>C₁V₁ + C₂V₂ = C₃V₃</u>

<u>40×V₁ + 10×V₂ = 28×20</u>

So,

40V₁ + 10V₂ = 560........................................(2)

Solving 1 and 2 as:

V₂ = 20 - V₁

Applying in 2

40V₁ + 10(20 - V₁)  = 560

40V₁ + 200 - 10V₁ = 560

30V₁ = 360

<u>V₁ = 12 L</u>

So,

<u>V₂ = 20 - V₁ = 8L</u>

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