All categories

2 years ago

What is the arc length when theta=pie/3 and the radius is 5 cm

Mathematics

1 answer:

Jobisdone [24]2 years ago

5 0

Answer:

Hey There!

Let's solve....

Radius=5cm

Angle = pi/3

Therefore arc length= Radius×angle

$= 5 \times \frac{\pi}{3} \\ \\ let \: \pi \: be \: 3.14cm \: so \: \\ \\ 5 \times \frac{3.14}{3} \\ \\ = \frac{15.70}{3} \\ \\ = 5.23cm$

The arc length is 5.23 cm when Theta=pi/ 3 and radius is 5 cm.

<h2>I hope it is helpful to you...</h2><h3>Cheers!_________</h3>

You might be interested in

X: -3x + 14 = 4x -7

Luda [366]

-3x+14=4x-7 = x=3

The answer is x=3

7 0

3 years ago

Read 2 more answers

in a poll 303 students voted . nominee d received 2/3 of the votes how many votes did nominee d receive

Dmitry_Shevchenko [17]

Answer:

Nominee d receive 202 votes.

Step-by-step explanation:

Given : In a poll 303 students voted. Nominee d received $\frac{2}{3}$ of the votes.

To find : How many votes did nominee d receive ?

Solution :

The number of votes = 303

Nominee d received $\frac{2}{3}$ of the votes.

i.e. $n=\frac{2}{3}\times 303$

$n=2\times 101$

$n=202$

Therefore, nominee d receive 202 votes.

5 0

3 years ago

Helpppp plssss!! Show your work!!<br><br>Thanks

Eduardwww [97]

Slope of a Line Passing through two points (x₁ , y₁) and (x₂ , y₂) is given by :

$\heartsuit\;\;Slope(m) = \frac{y_1 - y_2}{x_1 - x_2}$

Given Points are (-3 , 5) and (6 , -1)

here x₁ = -3 and x₂ = 6 and y₁ = 5 and y₂ = -1

$\heartsuit\;\;Slope(m) = \frac{5 + 1}{-3 - 6} = \frac{6}{-9} = \frac{-2}{3}$

Option D is the Answer

4 0

4 years ago

P is located at -23 and q is located at 18. what is the best distance between the points

Rina8888 [55]

Distance equals final position minus initial position.

d=18--23

d=18+23

d=41 units

5 0

3 years ago

Read 2 more answers

I am confused on how to solve this using L'hopital's<br> lim→0 (5^x - 3^x)/x

kupik [55]

Answer:

Same here

Step-by-step explanation:

6 0

3 years ago