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4 years ago

Write 171 in 3 as a unit rate

Mathematics

1 answer:

eduard4 years ago

4 0

The answer is 57 units .

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Directions: Write <> or = between each pair of rational numbers

rodikova [14]

Answer:

-2 5/12 > -2 3/4

-92 < -15/16

Step-by-step explanation:

8 0

4 years ago

Multiply 8x(3/4y+4) using distributive property

katrin [286]

6xy+32

You multiply 8x by each number and get

24/4xy+32 You can simplify the 24/4 to get six. so your answer is

6xy+32

4 0

3 years ago

Haw many ways can 8 books be arranged on a shelf

Juliette [100K]

there are 64 ways to rearrange books on a shelf

3 0

3 years ago

Read 2 more answers

Eli attended a concert. The decibel level of the music averaged 110 decibels but varied by 28 decibels from the average. Enter a

musickatia [10]

Answer:

The decibel range is $82\leq d\leq 138$

Step-by-step explanation:

Let

d -----> the decibel level of the music

we know that

The absolute value of the difference of the decibel level of the music and its average, must be less than or equal to 28 decibels

The absolute value that represent this problem is

$\left|d-110\right|\le28$

Solve the absolute value

<em>First solution (positive)</em>

$+(d-110)\le28$

Adds 110 both sides

$d\le28+110$

$d\le138$

<em>Second solution (negative)</em>

$-(d-110)\le28$

Multiply by -1 both sides

$(d-110)\ge-28$

Adds 110 both sides

$d\ge-28+110$

$d\ge82$

therefore

The decibel range is

$82\leq d\leq 138$

8 0

4 years ago

In July 2005, the internet was linked by a global network of about 353 million host computers. The number of host computers has

aalyn [17]

Answer:

$N(t) = 37.1(1.38)^t$

Step-by-step explanation:

Exponential function:

An exponential function has the following format:

$N(t) = N(0)(1+r)^t$

In which N(0) is the initial value and r is the rate of change, as a decimal.

37.1 million in July 1998

This means that $N(0) = 37.1$

$N(t) = 37.1(1+r)^t$

In July 2005, the internet was linked by a global network of about 353 million host computers.

This is 2005 - 1998 = 7 years, so $N(7) = 353$ . We use this to find r.

$N(t) = 37.1(1+r)^t$

$353 = 37.1(1+r)^7$

$(1+r)^7 = \frac{353}{37.1}$

$\sqrt[7]{(1+r)^7} = \sqrt[7]{\frac{353}{37.1}}$

$1 + r = (\frac{353}{37.1})^{\frac{1}{7}}$

$1 + r = 1.38$

The formula is:

$N(t) = 37.1(1.38)^t$

5 0

3 years ago