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4 years ago

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help pleeesea!!!!!!!!!!!.Trina downloaded 3 music albums and 5 audio books one week at a cost of $49.60. The next week she downl

oaded 1 music album and 2 audio books at a cost of $20.50. Her mother wants to write a system of equations to determine the price of one music album and one audio book. She uses the variables x and y. She lets x represent the cost of one music album. What will y represent?

2 answers:

Ad libitum [116K]4 years ago

8 0

Y is the Audio Book.

"determine the price of one music album and one audio book"

"She lets x represent the cost of one music album."

According to this information "One Audio Book" should be the correct answer. Have a great day!

ICE Princess25 [194]4 years ago

5 0

Answer:

y will represent the cost of one audio book.

Step-by-step explanation:

Here, the cost of 3 music albums and 5 audio books is $49.60 and 1 music album and 2 audio books is $20.50,

Since, there are two unknown values,

First one is the cost of one music album,

Second one is the cost of one audio book,

We know that, for finding an unknown value we take a variable,

If we have variables x and y in which x represent the cost of one music album, then y must represent the cost of one audio album.

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3 years ago

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Answer:

(1) P( $\bar X$ < 26 inches) = 0.0436

(2) P(27.5 inches < $\bar X$ < 28.5 inches) = 0.2812

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We are given that the mean vertical leap of all NBA players is 28 inches. Suppose the standard deviation is 7 inches and 36 NBA players are selected at random.

Firstly, Let $\bar X$ = mean vertical leap for the 36 players

Assuming the data follows normal distribution; so the z score probability distribution for sample mean is given by;

Z = $\frac{\bar X - \mu}{\frac{\sigma}{\sqrt{n} } }$ ~ N(0,1)

where, $\mu$ = population mean vertical leap = 28 inches

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P( $\bar X$ < 26) = P( $\frac{\bar X - \mu}{\frac{\sigma}{\sqrt{n} } }$ < $\frac{26-28}{\frac{7}{\sqrt{36} } }$ ) = P(Z < -1.71) = 1 - P(Z $\leq$ 1.71)

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(2) <em>Now, here sample of NBA players is 26 so n = 26.</em>

Probability that the mean vertical leap for the 26 players will be between 27.5 and 28.5 inches is given by = P(27.5 inches < $\bar X$ < 28.5 inches) = P( $\bar X$ < 28.5 inches) - P( $\bar X$ $\leq$ 27.5 inches)

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P( $\bar X$ $\leq$ 27.5) = P( $\frac{\bar X - \mu}{\frac{\sigma}{\sqrt{n} } }$ $\leq$ $\frac{27.5-28}{\frac{7}{\sqrt{26} } }$ ) = P(Z $\leq$ -0.36) = 1 - P(Z < 0.36)

= 1 - 0.64058 = 0.35942

Therefore, P(27.5 inches < $\bar X$ < 28.5 inches) = 0.64058 - 0.35942 = 0.2812

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