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Gekata [30.6K]
2 years ago
15

Help please I'm stuck on this question

Mathematics
2 answers:
oee [108]2 years ago
8 0

Answer:

120 y2

Step-by-step explanation:

The floor consists of a square and a triangle

area of square = 10² = 100 yd²

area of triangle =  bh ( b is the base and h the height )

Here b = 4 and h = 10 , then

area =  × 4 × 10 = 2 × 10 = 20 yd²

company needs 100 + 20 = 120 yd²

Ann [662]2 years ago
8 0

Answer:

120 yd²

Step-by-step explanation:

The floor consists of a square and a triangle

area of square = 10² = 100 yd²

area of triangle = \frac{1}{2} bh ( b is the base and h the height )

Here b = 4 and h = 10 , then

area = \frac{1}{2} × 4 × 10 = 2 × 10 = 20 yd²

company needs 100 + 20 = 120 yd²

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What value of ​x satisfies the equation 6.4−2x−6.63x=610.5 ?
Nesterboy [21]
6.4 - 2x - 6.63x = 610.5
subtract 6.4 from both sides 
-2x -6.63x =604.1
collect like terms 
-8.63x = 604.1
divide both sides by -8.63

x= -70

4 0
3 years ago
Please help me. I need help
mel-nik [20]
<h3>Answer:</h3>

  a.  -(3√13)/13

<h3>Step-by-step explanation:</h3>

The cosine can be found from the tangent by way of the secant.

  tan(θ)² +1 = sec(θ)² = 1/cos(θ)²

Then ...

  cos(θ) = ±1/√(tan(θ)² +1)

The <em>cosine is negative in the second quadrant</em>, so we will choose that sign.

  cos(θ) = -1/√((-2/3)² +1) = -1/√(4/9 +1) = -1/√(13/9)

  cos(θ) = -3/√13 = -(3√13)/13 . . . . . matches your selection A

3 0
3 years ago
Read 2 more answers
What is the common multiples of 5,3,8
tangare [24]

Answer:

120.

Step-by-step explanation:

If you're asking for LCM the answer is 120.

3 0
3 years ago
Read 2 more answers
Help me pls!!!!!!!!!
Dominik [7]

Answer:

x^2+18=-9x : x = -3, x = -6

Step-by-step explanation:

x^2+18=-9x

Add 9x to both sides:

x^2+18+9x=-9x+9x

Simplify:

x^2+9x+18=0

Solve with the quadratic formula:

For a quadratic equation of the form ax^2+bx+c=0 the solutions are:

x_{1,\:2}=\frac{-b\pm \sqrt{b^2-4ac}}{2a}

For a=1,\:b=9,\:c=18:\quad x_{1,\:2}=\frac{-9\pm \sqrt{9^2-4\cdot \:1\cdot \:18}}{2\cdot \:1}

x =\frac{-9 + \sqrt{9^2-4\cdot \:1\cdot \:18}}{2\cdot \:1} : -3

x =\frac{-9 - \sqrt{9^2-4\cdot \:1\cdot \:18}}{2\cdot \:1} : -6

The solution to the quadratic equation are:

x=-3,\:x=-6

Hope I helped. If so, may I get brainliest and a thanks?

Thank you, have a good day!

6 0
3 years ago
Are 2/5 4/10 6/15 and 8/20 proportional?
Over [174]
Yes, since you can multiply 2/5 numerator and denominator to get the rest of the fractions, it makes them all equivalent.
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3 years ago
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