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2 years ago

Help please I'm stuck on this question

Mathematics

2 answers:

oee [108]2 years ago

8 0

Answer:

120 y2

Step-by-step explanation:

The floor consists of a square and a triangle

area of square = 10² = 100 yd²

area of triangle = bh ( b is the base and h the height )

Here b = 4 and h = 10 , then

area = × 4 × 10 = 2 × 10 = 20 yd²

company needs 100 + 20 = 120 yd²

Ann [662]2 years ago

8 0

Answer:

120 yd²

Step-by-step explanation:

The floor consists of a square and a triangle

area of square = 10² = 100 yd²

area of triangle = $\frac{1}{2}$ bh ( b is the base and h the height )

Here b = 4 and h = 10 , then

area = $\frac{1}{2}$ × 4 × 10 = 2 × 10 = 20 yd²

company needs 100 + 20 = 120 yd²

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Find the volume of a cube that has the following dimensions:length=2x^2 width=x^3 height=x^2-6x+5 A) 4x^7-3x^6+8x^5 B) 2x^12-12x

fomenos

Answer:

Option D. 2x⁷ - 12x⁶ + 10x⁵

Step-by-step explanation:

From the question given:

Length (L) = 2x²

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V = 2x² × x³ × x² - 6x + 5

V = (2x²) (x³) (x² - 6x + 5)

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Clear bracket

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Therefore, the volume of the cube is 2x⁷ - 12x⁶ + 10x⁵

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Step-by-step explanation:

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