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maw [93]
3 years ago
7

If a medium pizza costs $5 and a large pizza is $8, write an equation in standard form that models the possible combinations of

you have $40. (Let m=medium and l=large.)
Mathematics
1 answer:
stealth61 [152]3 years ago
5 0
<span>NEVER use a lower case L as a variable
.
$5M+$8L=$45
.
Medium only:
$5M+$8(0)=$45
$5M=$45
M=9</span>
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3. A fast food joint sells 5 boxes of chicken nuggets for $33.90. Another fast food joint sells 4 boxe:
mrs_skeptik [129]
33.90/5= 6.78 or 26.88/4= 6.72. The 4 boxes of chicken fingers has the cheaper unit price
3 0
3 years ago
A sample size 25 is picked up at random from a population which is normally
Margarita [4]

Answer:

a) P(X < 99) = 0.2033.

b) P(98 < X < 100) = 0.4525

Step-by-step explanation:

To solve this question, we need to understand the normal probability distribution and the central limit theorem.

Normal Probability Distribution:

Problems of normal distributions can be solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the z-score of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X.

Central Limit Theorem

The Central Limit Theorem estabilishes that, for a normally distributed random variable X, with mean \mu and standard deviation \sigma, the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean \mu and standard deviation s = \frac{\sigma}{\sqrt{n}}.

For a skewed variable, the Central Limit Theorem can also be applied, as long as n is at least 30.

Mean of 100 and variance of 36.

This means that \mu = 100, \sigma = \sqrt{36} = 6

Sample of 25:

This means that n = 25, s = \frac{6}{\sqrt{25}} = 1.2

(a) P(X<99)

This is the pvalue of Z when X = 99. So

Z = \frac{X - \mu}{\sigma}

By the Central Limit Theorem

Z = \frac{X - \mu}{s}

Z = \frac{99 - 100}{1.2}

Z = -0.83

Z = -0.83 has a pvalue of 0.2033. So

P(X < 99) = 0.2033.

b) P(98 < X < 100)

This is the pvalue of Z when X = 100 subtracted by the pvalue of Z when X = 98. So

X = 100

Z = \frac{X - \mu}{s}

Z = \frac{100 - 100}{1.2}

Z = 0

Z = 0 has a pvalue of 0.5

X = 98

Z = \frac{X - \mu}{s}

Z = \frac{98 - 100}{1.2}

Z = -1.67

Z = -1.67 has a pvalue of 0.0475

0.5 - 0.0475 = 0.4525

So

P(98 < X < 100) = 0.4525

6 0
3 years ago
50 points! <br> Solve: <br> 5a + 6.9 = 3.6a +16.28
icang [17]
A = 6.7 :) hope this helps I double checked
6 0
3 years ago
Read 2 more answers
The statement below describes a situation in which opposite quantities combine to make 0. Is the statement true or false?
Lerok [7]
True

1/2 (up the hill) - 1/2 (down the hill) = 0
6 0
3 years ago
Factor completely 2w^5-10w^3
Kryger [21]
2w^5-10w^3=2w^3(w^2-5)
8 0
4 years ago
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