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Gelneren [198K]
3 years ago
9

I need a bit of help! I can't figure out how to convert this. Thank you so much!

Mathematics
1 answer:
Kitty [74]3 years ago
5 0
7.72 Lbs/week

Hope this helps :) 
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5x2 +14x = 3<br> How do you complete the square
katovenus [111]
If I’m correct negative one half
5 0
3 years ago
The m∠P is three less than twice the measure of ∠Q. If ∠P and ∠Q are supplementary angles, find the measures of both angles.
notka56 [123]

Answer:

m∠P =119

m∠Q = 61

Step-by-step explanation:

m∠P =  2(∠Q)-3    or p=2(q)-3

supplementary angles so they combine to equal 180!

soooooo we can take  

q+p=180

input what p equals and you get

q+ 2(q)-3=180

3q-3=180

3q=183

q=61

now we have what m∠Q is, so just subtract that from 180 to get m∠P

180-61=119

7 0
3 years ago
Find the length of the missing side of the triangle below. Give both exact and approximate answer. Round answer to nearest tenth
Drupady [299]

Answer:

c = √85

c = 9.2

Step-by-step explanation:

a² + b² = c²

7² + 6² = c²

49 + 36 = c²

85 = c²

c = √85

c = 9.2

4 0
3 years ago
R+r+2r-r+4r combine like terms and solve
goldenfox [79]

R+r+2r-r+4r

R + r + 2R + 4r = R+7r

R+7r - -r =

R+6r

6 0
3 years ago
A typical cup of coffee contains about 100 mg of caffeine and every hour approximately 16% ofthe amount of caffeine inthe body i
Over [174]

Answer:

a) \frac{dC}{dt} = rC

And for this case we can rewrite the model like this:

\frac{dC}{C} = r dt

If we integrate both sides we got:

ln C = rt + k

If we use exponentials for both sides we got:

C = e^{rt} e^k = C_o e^{rt}

For this case C_o = 100 mg and r = -0.16

So then our model would be given by:

C(t) = 100 e^{-0.16 t}

Where t represent the number of hours

b) C(5) = 100 e^{-0.16*5}= 44.9329

Step-by-step explanation:

Part a

For this case we can assume the proportional model given by:

\frac{dC}{dt} = rC

And for this case we can rewrite the model like this:

\frac{dC}{C} = r dt

If we integrate both sides we got:

ln C = rt + k

If we use exponentials for both sides we got:

C = e^{rt} e^k = C_o e^{rt}

For this case C_o = 100 mg and r = -0.16

So then our model would be given by:

C(t) = 100 e^{-0.16 t}

Where t represent the number of hours

Part b

For this case we can replace the value t=5 into the model and we got:

C(5) = 100 e^{-0.16*5}= 44.9329

7 0
3 years ago
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