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timofeeve [1]
2 years ago
14

Roy is 11 years old and his uncle is 59 years old. How many years ago was Roy’s uncle 7 times as old as Roy?

Mathematics
1 answer:
DiKsa [7]2 years ago
8 0

Answer:

answer : 3 years ago

Step-by-step explanation:

Let x years ago.

59−x=7(11−x)

59−x=77−7x

6x=18

x=3

=3 years ago

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What is the volume of the cylinder below? Use 3.14 for pi and I round to the nearest tenth
Rainbow [258]

Answer:

Option (4).

Step-by-step explanation:

Formula to calculate the volume of a cylinder is,

V = πr²h

Here r = radius of the cylinder

h = Height of the cylinder

From the figure attached,

r = \frac{13}{2}=6.5 cm

h = 11 cm

Now we substitute the values of h and r in the formula,

V = π(6.5)²(11)

   = 464.75π

   = 1459.32

   ≈ 1459.3 cm³

Therefore, volume of the given cylinder is 1459.3 cm³

Option (4) will be the answer.

6 0
3 years ago
Write two multiplication sentences that have a product of 16
Hatshy [7]
2 times 8=16
4 times 4=16
7 0
3 years ago
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The sample data below shows the number of hours spent by five students over the weekend to prepare for Monday's Business Statist
Levart [38]

Answer:

8.5 hrs

Step-by-step explanation:

-A 75th percentile mathematically means that  75% of the time data points are below that value and 25% of the time are above that value.

-We plot the given our data {3 12 2 3 5} to determine the 75th percentile

#We can use alcula.com to plot our boxplot.

-From the plot, we find our 75th percentile to be 8.5 hrs

Hence, 75% of the time the number of hours spent to prepare was less than 8.5hrs.

6 0
3 years ago
PLS HELP 20 POINTS!!
Nitella [24]

Answer:

1. 144km

2. 96 km

3. 200 km

Step-by-step explanation:

see image

5 0
1 year ago
Read 2 more answers
Exhibit B: A restaurant has tracked the number of meals served at lunch over the last four weeks. The data shows little in terms
Mekhanik [1.2K]

Answer:

Option E is correct.

The expected number of meals expected to be served on Wednesday in week 5 = 74.2

Step-by-step Explanation:

We will use the data from the four weeks to obtain the fraction of total days that number of meals served at lunch on a Wednesday take and then subsequently check the expected number of meals served at lunch the next Wednesday.

Week

Day 1 2 3 4 | Total

Sunday 40 35 39 43 | 157

Monday 54 55 51 59 | 219

Tuesday 61 60 65 64 | 250

Wednesday 72 77 78 69 | 296

Thursday 89 80 81 79 | 329

Friday 91 90 99 95 | 375

Saturday 80 82 81 83 | 326

Total number of meals served at lunch over the 4 weeks = (157+219+250+296+329+375+326) = 1952

Total number of meals served at lunch on Wednesdays over the 4 weeks = 296

Fraction of total number of meals served at lunch over four weeks that were served on Wednesdays = (296/1952) = 0.1516393443

Total number of meals expected to be served in week 5 = 490

Number of meals expected to be served on Wednesday in week 5 = 0.1516393443 × 490 = 74.3

Checking the options,

74.3 ≈ 74.2

Hence, the expected number of meals expected to be served on Wednesday in week 5 = 74.2

Hope this Helps!!!

8 0
3 years ago
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