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natka813 [3]
2 years ago
7

Which of the following equations could be parallel to the equation x = 5

Mathematics
1 answer:
seraphim [82]2 years ago
4 0

Answer:

B

Step-by-step explanation:

x = 5 is the equation of a vertical line parallel to the y- axis

The equation of a line parallel to it must have the same form, that is

x = - 2 ← vertical line parallel to x = 5

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I have two and one half squares and i want to divide them by one fourth. How many pieces would i have?
Nutka1998 [239]

2+½, is just 2½, now divided by 1/4.

let's first convert the mixed fraction to improper, and then divide.


\bf \stackrel{mixed}{2\frac{1}{2}}\implies \cfrac{2\cdot 2+1}{2}\implies \stackrel{improper}{\cfrac{5}{2}}
\\\\[-0.35em]
~\dotfill\\\\
\cfrac{5}{2}\div \cfrac{1}{4}\implies \cfrac{5}{2}\cdot \cfrac{4}{1}\implies \cfrac{5}{1}\cdot \cfrac{4}{2}\implies 5\cdot 2\implies 10

3 0
3 years ago
Naomi has earned $54 mowing lawns
Vinil7 [7]

Answer:

9$ per hour

Step-by-step explanation:

if its 54 dollars in 2 days all you have to do is add the total of hours togther and divided it sk it would be 54 divided by 6 because that is the total of hours in 2 days. which gets you 9 dollars per hour

4 0
3 years ago
Read 2 more answers
Which equation could be used to create the graph?
Eva8 [605]

Answer:

C

Step-by-step explanation:

The equation of a line passing through the origin is

y = mx ( m is the slope )

Calculate m using the slope formula

m = (y₂ - y₁ ) / (x₂ - x₁ )

with (x₁, y₁ ) = (0, 0) and (x₂, y₂ ) = (9, 3) ← 2 points on the line

m = \frac{3-0}{9-0} = \frac{3}{9} = \frac{1}{3}, thus

y = \frac{1}{3} x

Or

y = \frac{x}{3} → C

6 0
3 years ago
Read 2 more answers
X + 4y = 13 <br> x - y = 3<br> systems of equations I need help on a couple of these like ASAP
lara31 [8.8K]
A.)
Slope:-1/4
Y intercept: (0,13/4)
X intercepts:(13,0)
B.)
X intercepts:(3,0)
Y intercepts:(0,-3)
4 0
3 years ago
Figure ABCD is transformed to obtain figure A′B′C′D′:
Kisachek [45]

Step-by-step explanation:

part A:

ABCD is transformed to obtain figure A′B′C′D′:

1) by reflection over x-axis, obtain the image :

A(-4,-4) B(-2,-2) C(-2, 1) D(-4, -1)

2) by translation T (7 0), obtain the image :

A'(3,-4) B'(5,-2) C'(5, 1) D'(3, -1)

part B:

the two figures are congruent.

the figures that transformed by reflection either or translation will obtain the images with the same shape and size (congruent)

6 0
3 years ago
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