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romanna [79]
3 years ago
13

What polygon is formed when 2 equilateral triangles that are congruent and share a side

Mathematics
1 answer:
zalisa [80]3 years ago
7 0

You form a rhombus.

Draw an equilateral triangle, and then mirror it around its base. All the sides are clearly equal, because they are all sides of the same equilateral triangle.

Moreover, the top and bottom angle are 60°, because they are angles of an equilateral triangle, while the left and right angles are 120, because they're 60+60 angles.

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Find the value of y when x equals 0 <br>-7x+3y=30​
algol13
Y=10 this is your answer
6 0
1 year ago
S= 2pier^2 + 2pierh , solve for h
maw [93]
2pier^2+2pierh=S\ \ \ |subtract\ 2pier^2\ from\ both\ sides\\\\2pierh=S-2pier^2\ \ \ \ |divide\ both\ sides\ by\ 2pier\\\\\boxed{h=\dfrac{S-2pier^2}{2pier}\ other\ form\ h=\dfrac{S}{2pier}-r}
3 0
3 years ago
Joseph put a 30% down payment on a house. What fraction of a down payment did Joseph put on a house?
marshall27 [118]
3/10 is the fraction that matches 30%.

7 0
3 years ago
Suppose ABCD is a rectangle. Find AB and AD if point M is the midpoint of
Dvinal [7]
We know that
Perimeter=2AB+2AD=34 in-----> AB+AD=17-----> AB=17-AD-----> equation 1

MA=MD
MA²=AB²+(AD/2)²
for the triangle AMD
AD²=[MA²+MD²]----> AD²=2*[MA²]----> AD²=2*[AB²+(AD/2)²]---> equation 2

I substitute 1 in 2

AD²=2*[(17-AD)²+(AD/2)²]----> AD²=2*[289-34AD+AD²+0.25AD²]

AD²=578-68AD+2.50AD²--------> 1.50AD²-68AD+578

1.50AD²-68AD+578=0

 using a graph tool to solve the quadratic equation

see the attached figure

AD1=11.33 in

AD2=34 in----------is not solution because (AB+AD=17)

Solution is AD=11.33 in

AB=17-11.33--------> 17-11.33-----> AB=5.67 in

 the answer is

AD=11.33 in

<span>AB=5.67 in</span>

 

4 0
3 years ago
Brainliest reward …… please quick
strojnjashka [21]

Answer:

3 boxes of fertilisers.

Solving steps:

<u>Part A</u>:

Area of the garden, rectangle:

Length * Width

12 * 7

84 m²

Area of patio:

\sf{\frac{1}{2}  * base *height

\sf{\frac{1}{2}  * 6*3

\sf{9 m²

Area of grass:

Area of the garden - Area of patio

84 m² - 9 m²

75 m²

<u>Part B</u>:

32 m² ↔  1 box

1 m²    ↔ \sf{ \frac{1}{32} box

75 m²  ↔ \sf{ \frac{1}{32} *75 boxes

75 m²  ↔ 2.34375 boxes

  • As she cannot buy exact 2.34375 boxes.

She should buy 3 boxes of fertilisers.

6 0
2 years ago
Read 2 more answers
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