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3 years ago

13

What polygon is formed when 2 equilateral triangles that are congruent and share a side

1 answer:

zalisa [80]3 years ago

7 0

You form a rhombus.

Draw an equilateral triangle, and then mirror it around its base. All the sides are clearly equal, because they are all sides of the same equilateral triangle.

Moreover, the top and bottom angle are 60°, because they are angles of an equilateral triangle, while the left and right angles are 120, because they're 60+60 angles.

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Please help and write the steps to fine the answer (ignore the erasings)

podryga [215]

Answer: 1/50

Step-by-step explanation:

= 2 * 10^-2 * 2^0

= 2 * 1/10^2 * 1 (2^0=1)

= 2/100

= 1/50

3 0

2 years ago

Read 2 more answers

Rx+9/5=h, Solve for the value of x

muminat

rx+(9/5)=h

rx=h-(9/5)

x=(h-(9/5))/r

5 0

3 years ago

Helppppppppppppppppppppp!!!!!!!!!1

vitfil [10]

Answer: I need help too

Step-by-step explanation:

I think is -6

6 0

2 years ago

What is PA <br> Enter your answer in the box

SSSSS [86.1K]

Answer:

3

Step-by-step explanation:

P is the in-center

⇒PA=PE=PD because they are in-radius of the in-circle

We know that, tangent segments drawn from a point outside the circle are always equal in length

⇒DK=EK=7.2

In right triangle PKE,

using Pythagoras' Theorem : $PK^{2}=PE^{2}+KE^{2}$

⇒ $PE^{2}=PK^{2}-KE^{2}$

⇒ $PE=\sqrt{PK^{2}-KE^{2} }$

⇒ $PE^{2}=\sqrt{7.8^{2}-7.2^{2}} }$

⇒ $PE=3$

Therefore, $PA=3$

3 0

2 years ago

Find all points on the curve y = cos x, 0 ≤ x ≤ 2π, where the tangent line is parallel to the line y = -x.

andre [41]

Answer:

90⁰

Step-by-step explanation:

y=cosx

y'= -sinx

eqñ of tangent is y=-x

slope of tangent =-1

we know...

slope of tangent = y' or derivative of y

-sin x = -1

sin x= 1

x = 90⁰

7 0

2 years ago